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zhannawk [14.2K]
3 years ago
12

Which describes the volume of 1 mol of gas at standard temperature and pressure?

Chemistry
1 answer:
Setler79 [48]3 years ago
3 0

Volume of 1  mol of gas at standard temperature and pressure is 22.4 L.

That is using ideal gas equation:

PV = nRT

P=pressure

V=volume

n=number of moles

R=gas constant

T=temperature

at STP,

P=1 atm

T=273K

n=1(given)

Putting all the values in the equation will give,

V= 22.4 L

So, the answer is :

The volume of 1 mol of gas at standard temperature and pressure is 22.4 L.


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Metallic bonds are the attractive forces between the metal cations and the sea of electrons.

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Which compound has the strongest hydrogen bonding between its molecules? 1. HBr 2. HF 3. HCl 4. HI
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Equation

B2Br6+HNO3=B(NO3)3+HBr

B=2                                 B=1

BR=6                             BR=1

H=1                                  H=1

N=1                                  N=3

O=3                                 O=9

ANSWER

B2Br6 + 6HNO3 → 2B(NO3)3 + 6BrH

B=2                                 B=2

BR=6                             BR=6

H=6                                  H=6

N=6                                  N=6

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HOPE THIS HELPS

4 0
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A critical reaction in the production of energy to do work or drive chemical reactions in biological systems is the hydrolysis o
MAVERICK [17]

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Explanation :

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Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given balanced chemical reaction is,

ATP(aq)+H_2O(l)\rightarrow ADP(aq)+HPO_4^{2-}(aq)

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Q=\frac{[ADP][HPO_4^{2-}]}{[ATP]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Given:

[ATP] = 5.0 mM

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[HPO_4^{2-}] = 5.0 mM

Now put all the given values in this expression, we get

Q=\frac{(0.60)\times (5.0)}{(5.0)}=0.60mM=0.60\times 10^{-3}M

Now we have to calculate the value of \Delta G_{rxn}.

The formula used for \Delta G_{rxn} is:

\Delta G_{rxn}=\Delta G^o+RT\ln Q    ............(1)

where,

\Delta G_{rxn} = Gibbs free energy for the reaction  = ?

\Delta G_^o =  standard Gibbs free energy  = -30.5 kJ/mol

R = gas constant = 8.314\times 10^{-3}kJ/mole.K

T = temperature = 37.0^oC=273+37.0=310K

Q = reaction quotient = 0.60\times 10^{-3}

Now put all the given values in the above formula 1, we get:

\Delta G_{rxn}=(-30.5kJ/mol)+[(8.314\times 10^{-3}kJ/mole.K)\times (310K)\times \ln (0.60\times 10^{-3})

\Delta G_{rxn}=-49.6kJ/mol

Therefore, the value of \Delta G_{rxn} is -49.6 kJ/mol

6 0
3 years ago
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