Answer:
0.144M
Explanation:
First, let us write a balanced equation for the reaction. This is illustrated below:
HNO3 + KOH —> KNO3 + H20
From the equation,
nA = 1
nB = 1
From the question given, we obtained the following:
Ma =?
Va = 30.00mL
Mb = 0.1000M
Vb = 43.13 mL
MaVa / MbVb = nA/nB
Ma x 30 / 0.1 x 43.13 = 1
Cross multiply to express in linear form
Ma x 30 = 0.1 x 43.13
Divide both side by 30
Ma = (0.1 x 43.13) /30 = 0.144M
The molarity of the nitric acid is 0.144M
Explanation:
C3H8 + 502 ----> 3CO2 + 4H20
4NH3+7O2------> 4NO2+6H2O
2Al(NO3)3 + 3Na2S -------> Al2S3+6NaNO3
Answer:
M₂ = 0.9 M
Explanation:
Given data:
Initial Volume = V₁ = 250 mL
Initial molarity = M₁= 3 M
Final volume = 850 mL
Final molarity = ?
Solution:
M₁V₁ = M₂V₂
M₂ = M₁V₁ /V₂
M₂ = 3 M × 250 mL / 850 mL
M₂ = 750 M / 850
M₂ = 0.9 M
Since 1000 mg=1g
500mg=?
500/1000*1g=0.5g
Since we know that 500mg is 0.5g then divide 30g by 0.5g
30/0.5=60
Therefore the patients needs to take 60 tablets a day.
Hydrogen + oxygen --> water
59,1g + x = 528g
528g - 59,1 = x
x = 468,9g