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kondor19780726 [428]
3 years ago
8

Feather is dropped from 13 m high after it has fallen 3 m what is its acceleration

Physics
1 answer:
iogann1982 [59]3 years ago
4 0

Answer:

Explanation:

The constant acceleration of any object, neglecting air resistance and friction, is always -9.8. Proof:

s(t)=-4.9t^2+13 which is the position of this feather before it is dropped. The first derivative of position is velocity, so the velocity function for the feather is:

v(t)=-9.8t. We could find the velocity that the feather is experiencing at 3 seconds, but that is not what we are being asked. What we are being asked is the acceleration of the feather at 3 seconds. So we find the acceleration function of the feather:

a(t) = -9.8

It turns out that the time doesn't matter to acceleration due to gravity because feathers and elephants all fall under the same pull.

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What is the general relationship between earthquake epicenters and volcano positions along the Pacific coast of Mexico and Centr
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4 0
4 years ago
16. If "team A has 3 of its bocce balls closer to the pallino than any of their opponent's balls, who wins the
Gre4nikov [31]

Answer:

Team A wins the frame with three points. The opposing team gets zero points for the frame.

Explanation:

7 0
3 years ago
A crate filled with delicious junk food rests on a horizontal floor. Only gravity and the support force of the floor act on it,
stealth61 [152]

The words "... as shown ..." tell us that there's a picture that goes along
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4 0
3 years ago
A 2.5 kg tribble is placed in a bucket and whirled in a 1.4 m radius vertical circle at a constant tangential speed. If the forc
Over [174]

Given that,

Mass of a tribble, m = 2.5 kg

Radius, r = 1.4 m

The force on the tribble from the bucket does not exceed 10 times its weight.

To find,

The maximum tangential speed.

Solution,

The force acting on the tribble is equal to the centripetal force.

F = 10mg

The formula for the centripetal force is given by :

F=\dfrac{mv^2}{r}

v is maximum tangential speed

v=\sqrt{\dfrac{Fr}{m}} \\\\v=\sqrt{\dfrac{mgr}{m}} \\\\v=\sqrt{{10gr}} \\\\v=\sqrt{10\times 9.8\times 1.4} \\\\v=11.7\ m/s

So, the maximum tangential speed is 11.7 m/s.

8 0
3 years ago
328,000 mm + 137 m = ______________m?
svp [43]

Answer:

465m.

Explanation:

Convert all units to meters. So,

328 + 137 = 465m.

5 0
4 years ago
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