Question

Write the y-equation for a wave traveling in the negative x-direction with wavelength 50 cm, speed 4.0 m/s, and amplitude 5.0 cm.

Answer 1

Answer:

$y = A sin(2\pi(\dfrac{x}{50})+ 8 t)$

Explanation:

given,

wavelength, λ = 50 cm

speed, v = 4 m/s

Amplitude, A = 5 cm

general equation of the wave along x- axis

$y = A sin(2\pi(\dfrac{x}{\lambda})\pm \nu t)$

sign is positive when wave is traveling in negative direction

now,

$\nu = \dfrac{v}{\lambda}$

$\nu = \dfrac{4}{0.5}$

$\nu = 8\ s^{-1}$

inserting all the values

$y = A sin(2\pi(\dfrac{x}{50})+ 8 t)$

Hence, the y-equation of wave is equal to $y = A sin(2\pi(\dfrac{x}{50})+ 8 t)$