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Ber [7]
3 years ago
13

Owen is signing up for a gym membership with a one-time fee to join and then a

Mathematics
1 answer:
Katena32 [7]3 years ago
3 0
The cost of the monthly fee is 50$.. if the joining fee is 100.. take 200 and subtract that fee since it is included in the total. You’re left with 100. Note, the 200 is calculated for a 2 month period, so split the remaining 100 ,from the total 200, into 2. You’re left with 50 each month.

T=(C-100)/2 (T being 1 month) (C being the total cost/200)

Hopefully

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Solve and reduce to lowest terms:<br> 6 / 11 x 1 / 3
zysi [14]

Answer:

2/11

Step-by-step explanation:

6/11 x 1/3 =

6/33 =

2/11

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3 years ago
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aleksandr82 [10.1K]
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4 years ago
Solve the equation 0.3 = -15z.
melamori03 [73]

Answer:

z = - 0.02

Step-by-step explanation:

0.3 = -15z

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6 0
3 years ago
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I need help with exercises 3,4, and 6 please show all work and don’t answer number 5 just tell me if it is correct
joja [24]
*If you need me to do #5, DM me!

3. 
The area of a triangle can be given by (just plug and chug as always):
A_t = \frac{1}{2} bh = \frac{1}{2}(3)(4) = 6ft^2
The area of the triangle is 6ft².

4. I will divide into a triangle and a rectangle (because the actual equation for the area of a pentagon requires it to be a perfect pentagon). Let's do the triangle first (height is 3 because you subtract 12 from 15):
A_t = \frac{1}{2} bh = \frac{1}{2}(8)(3) = 12m^2
A_r = bh = 12(8) = 96m^2
Now we just add them:
96+12 = 108m^2

So, the area of that pentagon is 108m².

5. You are actually wrong on this one because the area of a triangle is:
A_t = \frac{1}{2}bh
So, just halve your answer and it will be correct.

6. We can just split it into 4 triangles of equal area and then multiply the area of 1 triangle by 4 to get the total area. Let's do just that:
A_t = \frac{1}{2}bh = \frac{1}{2}(2.5)(5) = 6.25cm^2
Multiply by 4 to get total area:
6.25*4 = 25cm^2

So, the area of the given rhombus is 25cm².
8 0
4 years ago
The ellipse 14x2+2x+y2=114x2+2x+y2=1 has its center at the point (b,c)(b,c) where
Nana76 [90]
18x^2 + 2x + y^2 = 1 
<span>==> 18(x^2 + x/9) + y^2 = 1 </span>
<span>==> 18(x^2 + x/9 + 1/324) + y^2 = 1 + 1/18 </span>
<span>==> 18(x + 1/18)^2 + y^2 = 19/18 </span>
<span>==> (x + 1/18)^2/19 + (y - 0)^2/(19/18) = 1. </span>

<span>By comparing this to the standard form of an ellipse, the center is at (-1/18, 0). </span>
6 0
3 years ago
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