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Crank
3 years ago
8

Which expression is equivalent to 2x+2x+2y+2y

Mathematics
1 answer:
liq [111]3 years ago
3 0
4x plus 4y seems to be equal to that situation right there
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What is the volume of the solid shown above
tankabanditka [31]
539 cm^3

volume of the smaller cube is: 3•3•3 which equals 27.

volume of the bigger cube is: 8•8•8 which equals 512.

add those together and you get 539 cm^3







3 0
4 years ago
Help me asap pleaseeeeeeeeeeeeeeeeeee !!
grin007 [14]

Answer: rrxckz if i knew the answer i would give it to you.

8 0
3 years ago
Determining angle side relationships What are the angle measures in trainable ABC?
9966 [12]

Answer:

m∠A=90°, m∠B=60°, m∠C=30°

Step-by-step explanation:

step 1

Verify if the triangle ABC is a right triangle

Applying the Pythagoras theorem

12^{2}=6^{2}+(6\sqrt{3})^{2}

144=144 ----> is true

therefore

Is a right triangle

m∠A=90°

Find the measure of angle C

sin(C)=AB/BC

substitute

sin(C)=6/12=1/2

so

m∠C=30°

Find the measure of angle B

we know that

m∠C+m∠B=90°------> by complementary angles

so

m∠B=90°-30°=60°

5 0
3 years ago
At what rate is a car traveling, if it goes 157.5 miles in 2.5 hours?
Finger [1]

divide total miles by time:

157.5 / 2.5 = 63 miles per hour

4 0
3 years ago
A projectile is fired into the air with an initial vertical velocity of 160 ft/sec from ground level. How many seconds later doe
djverab [1.8K]

The maximum height of the projectile is the maximum point that can be gotten from the projectile equation

The projectile reaches the maximum height after 5 seconds

The function is given as:

\mathbf{h(t) = -16t^2 + 160t}

Differentiate the function with respect to t

\mathbf{h'(t) = -32t + 160}

Set to 0

\mathbf{h'(t) = -32t + 160 = 0}

So, we have:

\mathbf{-32t + 160 = 0}

Collect like terms

\mathbf{-32t =- 160 + 0}

\mathbf{-32t =- 160}

Solve for t

\mathbf{t = \frac{- 160}{-32}}

\mathbf{t = 5}

Hence, the projectile reaches the maximum after 5 seconds

Read more about maximum values at:

brainly.com/question/6636648

8 0
3 years ago
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