I am looking on the answers, and there is only one case, when a or b or c or d pass: 3|x-3| + 2 = 14. So I assume, that before two is plus. Then:
3|x-3|+2=14 |minus 2
3|x-3|=12 |divide 3
|x-3|=4
From absolute value definition you've got two ways:
x-3=4 or x-3=-4
x=7 or x=-1
And answer d) passes
Just plus in x for -3
f(x) = 4(-3)^2 + 3(-3) - 11
f (x) = 4(9) -9 - 11
f(x) = 36 - 20
f(x) = 16
Answer: 1.5 pizzas
Step-by-step explanation:
Answer:
the answer should be 152.6 ! just moving the decimal over to the left!!
Answer:
5.3
Step-by-step explanation:
Cos(68) = adjacent/hypotenuse
Cos(68) = 2/AC
AC = 2/cos(68)
AC = 5.3389343253
AC = 5.3
