I NEED HELP PLESE I BEG YOUUUU

anygoal [31]

Answer:

The size of the angle is between 180 and 360*. I cannot say the exact angle but my guess is correct and the correct answer is in between the 2 numbers.

Step-by-step explanation:

7 0

2 years ago

Which algebraic expression is equivalent to this expression? 6(3x-1)+9x

rusak2 [61]

Answer:

27x-6

Step-by-step explanation:

To distribute 6(3x-1) properly, 6 needs to be multiplied with 3x and -1.

6*(-1)=-6,

3x*6=18x.

Without simplifying, the answer we get from this is 18x+9x-6. 18x+9x=27x, so the algebraic expression equivalent to 6(3x-1)+9x is 27x-6.

5 0

3 years ago

Solve using law of sines or law of cosines!

malfutka [58]

Answer:

Part 5) The length of the ski lift is $1.15\ miles$

Part 6) The height of the tree is 18.12 m

Step-by-step explanation:

Part 5)

Let

A -----> Beginning of the ski lift

B -----> Top of the mountain

C -----> Base of mountain

we have

$b=0.75\ miles$

$A=20\°$

$C=180\°-50\°=130\°$ ----> by supplementary angles

Find the measure of angle B

Remember that the sum of the interior angles must be equal to 180 degrees

$B=180\°-A-C$

substitute

$B=180\°-20\°-130\°=30\°$

Applying the law of sines

$\frac{b}{sin(B)}=\frac{c}{sin(C)}$

substitute

$\frac{0.75}{sin(30\°)}=\frac{c}{sin(130\°)}$

$c=\frac{0.75}{sin(30\°)}(sin(130\°))$

$c=1.15\ miles$

Par 6)

see the attached figure with letters to better understand the problem

Applying the law of sines in the right triangle BDC

In the right triangle BDC 20 degrees is the complement of 70 degrees

$\frac{BC}{sin(70\°)}=\frac{x}{sin(20\°)}$

$BC=(sin(70\°))\frac{x}{sin(20\°)}$ -----> equation A

Applying the law of sines in the right triangle ABC

In the right triangle ABC 50 degrees is the complement of 40 degrees

$\frac{BC}{sin(40\°)}=\frac{x+15}{sin(50\°)}$

$BC=(sin(40\°))\frac{x+15}{sin(50\°)}$ -----> equation B

Equate equation A and equation B and solve for x

$(sin(70\°))\frac{x}{sin(20\°)}=(sin(40\°))\frac{x+15}{sin(50\°)}\\\\2.7475x=0.8391(x+15)\\\\2.7475x=0.8391x+12.5865\\\\2.7475x-0.8391x=12.5865\\\\x=6.60\ m$

Find the value of BC

$BC=(sin(70\°))\frac{6.6}{sin(20\°)}$

$BC=18.12\ m$

therefore

The height of the tree is 18.12 m

5 0

4 years ago

Martha Jackson had a $396.25 average monthly expenditure for clothing during the first quarter of the year. She spent $401.50 in

Sladkaya [172]

Answer: Martha spend $537.25 in june to have the same average as in the first quarter.

Step-by-step explanation:

Given that,

Average monthly expenditure for the first quarter= $396.25

Expenditure in April= $401.50

Expenditure in May= $250.00

Suppose, expenditure in June= x

To have the same average as in the first quarter, we have to take the average of the second quarter equals to the average of first quarter.

So,

Average monthly expenditure for the second quarter= $396.25

Using the formula of average for monthly expenditure for second qaurter as follow:

Average monthly expenditure for months April, May, and June= Sum of expenditure of April, May, and June divided by 3.

So,

396.25= (401.50 + 250.00 + x)/3

1188.75= 651.5 + x

x= 537.25

7 0

3 years ago

Hey school system is reducing the amount of dumpster loads of trash removed each week in week five there are 45 dumpster load th

natta225 [31]

Answer:

y = -3x + 60

Step-by-step explanation:

For the answer to the question above,

let x = number of weeks let y = amount of waste.

The linear equation may be expressed as,y = mx + b

m and b are the slope and y - intercept, respectively. Substituting the corresponding values,

(Week 5) 45 = 5m + b

(Week 10) 30 = 10m + b

Solving for m and b gives the values as m = -3 and b = 60. Thus, the equation is

y = -3x + 60

4 0

3 years ago