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xxTIMURxx [149]
3 years ago
14

X-3=x+13 solution or not

Mathematics
1 answer:
AfilCa [17]3 years ago
6 0
There’s no solution
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Simplify the imaginary number using the properties of exponents.<br> ¡102
olya-2409 [2.1K]

Answer:  Explanation: 102=2⋅51. i102=(i2)51=(−1)51=−1.

Step-by-step explanation:

3 0
3 years ago
Expression for the quotient of b divided by the difference of two minus 3
uysha [10]

Answer:

The required expression is

                                     \frac{b}{2 - 3}  = - b

Step-by-step explanation:

 

Difference of two minus three = 2-3

Quotient of b divided by the difference of two minus three is

                                             \frac{b}{2-3} = \frac{b}{-1} = - b

Therefore, the required expression is

                                                  \frac{b}{2-3}  \ \ \ \ \ \ \ \ or \ \ \ \ \ \ \ \  - b

7 0
3 years ago
A stationary store has decided to accept a large shipment of ball-point pens if an inspection of 19 randomly selected pens yield
Romashka [77]

Given Information:  

Probability of shipment accepted = p = 5%

Probability of shipment not accepted = q = 95%

Total number of pens = n = 19

Required Information:  

Probability of shipment being accepted with no more than 2 defective pens = P( x ≤ 2) = ?  

Answer:

P( x ≤ 2) = 0.933

Step-by-step explanation:

The given problem can be solved using Bernoulli distribution  which is given by

P(n, x) = nCx pˣqⁿ⁻ˣ  

The probability of no more than 2 defective pens means

P( x ≤ 2) = Probability of 0 defective pen + Probability of 1 defective pen + Probability of 2 defective pens

P( x ≤ 2) = P(0) + P(1) + P(2)

For P(0) we have p = 0.05, q = 0.95, n = 19 and x = 0

P(0) = 19C0(0.05)⁰(0.95)¹⁹

P(0) = (1)(1)(0.377)

P(0) = 0.377

For P(1) we have p = 0.05, q = 0.95, n = 19 and x = 1

P(1) = 19C1(0.05)¹(0.95)¹⁸

P(1) = (19)(0.05)(0.397)

P(1) = 0.377

For P(2) we have p = 0.05, q = 0.95, n = 19 and x = 2

P(2) = 19C2(0.05)²(0.95)¹⁷

P(2) = (171)(0.0025)(0.418)

P(2) = 0.179

Therefore, the required probability is

P( x ≤ 2) = P(0) + P(1) + P(2)

P( x ≤ 2) = 0.377 + 0.377 + 0.179

P( x ≤ 2) = 0.933

P( x ≤ 2) = 93.3%

Therefore, the probability that this shipment is accepted with no more than 2 defective pens is 0.933.

8 0
3 years ago
Which ordered pair in the form (a, b) is a solution of this equation?
Evgen [1.6K]

3a - 4b = 21


check (-2 , -3)


3(-2) -4(-3) =21


-6 +12  = 21


6 does not = 21  so NO


check (0 , 7)


3(0) -4(7) =21


0-28=21


-28 does not equal 21  so NO


check (-3 , -2)


3(-3) -4(-2) =21


-9 +8  = 21


1 does not = 21  so NO


check (7 , 0)


3(7) -4(0) =21


21  = 21

Choice D

5 0
3 years ago
(c) Evaluate P P(0). What might this stand for?
Naily [24]
I dont know but i think today you need a break being yourslef is awesome
3 0
3 years ago
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