The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
Substitute the known values in the above equation
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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Answer:
2427.26 $
Step-by-step explanation:
Just use this formula when you have such type of problems:
N = N° (1 + %)^t
Where N = final amount
N°= initial amount
t = peroid of time
Now let's solve:
N = 1000(1 + 0.03)^30
N = 2427.26
Answer:
angle is 45° which is constant
Step-by-step explanation:
We use formula for two vectors <u>a </u>and <u>b</u> to calculate angle θ between them by formula
cos θ = <u>a .</u> <u>b</u> / magnitude of <u>a </u> × magnitude of <u>b</u>
<u>Please see the attached file</u>
I can’t see the pic more can u edit it ms make it more bigger lol
