Answer:
B. 97
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find M as such
In which 
is the standard deviation of the population and n is the size of the sample.
How many students should be sampled to be within 1 drink of the population mean with 95% probability?
This is n when 
We know from preliminary studies that the standard deviation is around 5, so 
We round up, so the correct answer is:
B. 97
The answer would be option 1, mass divided by volume
total: 300
44% of 300= 132
25% of 300=75
132
-75
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The LCM of 210 and 450 is: 3150
Answer:
P(X≤164) = 0.16
Step-by-step explanation:
We are given that the weights of vegetables are normally distributed with mean 
= 172
Standard deviation, = 8
We need to calculate P(X≤164) we will use Z score to calculate this,
Z= 
= 
Z≤ -1
P(Z≤ -1) = 0.1587 (Using normal distribution table)
Rounding to nearest hundredth = 0.16
Now 0.5-0.34 = <u>0.16</u> or <u>16%</u>
