Anybody got snap i need help turning in my missing work

PLEASE HELP ASAP! I NEED TO PASS THIS TEST!

Nataly [62]

X^2+20x+10 that's the answer

4 0

3 years ago

Sudha earns ` 189 in a day and Radha earns ` 112 in a day. About how much will each of them earn in 30 days

Mariulka [41]

Answer:

the sudha and radha earns 5,670 and 3,360 respectively

Step-by-step explanation:

Since in the question it is mentioned that

Sudha earns 189 in a day

And, radha earns 112 in a day

so in 30 days, sudha earns

= 189 × 30 days

= 5,670

And, radha earns

= 112 × 30 days

= 3,360

Therefore the sudha and radha earns 5,670 and 3,360 respectively

8 0

3 years ago

Divide using long division. check your answers. 1. (x 3 – 13x 2 + 7x – 48) ÷ (x 2 + 3) 3. (x 3 + 5x 2 – 3x – 1) ÷ (x – 1) 5. (x

artcher [175]

1. We can conclude that the result of the division is $x-13$ with a remainder of $4x-9$ , or in other notation: $x-13+ \frac{4x-9}{x^2+3}$ . Check the steps in the first image.

3. We can conclude that the result of the division is $x^{2} +6x+3$ with a remainder of 2, or in other notation: $x^{2}+6x+3+ \frac{2}{x-1}$ . Check the steps in the firts image.

5. We can conclude that the result of the division is $x+1$ with a remainder of 5, or in other notation: $x+1+ \frac{5}{x-4}$ . Check the steps in the first image.

7. To check if $x+4$ is a factor of $x^{3}+3x^{2}-10x-24$ , we are going to perform long division. If the result of the long division has no remainder, $x+4$ is a factor of $x^{3}+3x^{2}-10x-24$ .
Since the result of the long division has no remainder, we can conclude that $x+4$ is a factor of $x^{3}+3x^{2}-10x-24$ . Check the steps in the second image.

9. To check if $x-3$ is a factor of $x^{3}+3x^{2}-10x-24$ , we are going to perform long division. If the result of the long division has no remainder, $x-4$ is a factor of $x^{3}+3x^{2}-10x-24$ .
Since the result of the long division has no remainder, we can conclude that $x-4$ is a factor of $x^{3}+3x^{2}-10x-24$ . Check the steps in the third image.

10. We can conclude that the result of the synthetic division is $-2x^{2}+9x+5$ . Check the steps in the fourth image.

3 0

3 years ago

How do find the domain and range of <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%7Bx-8%7D%7D" id="TexFormula1" tit

Kisachek [45]

$\sqrt{x-8}$ is undefined if the argument $x-8$ is negative, so you first need to require that

$x-8\ge0\implies x\ge8$

We're not done yet, though, because $\dfrac1{\sqrt{x-8}}$ still doesn't exist when $x=8$ , so we remove this from the domain and we're left with $x>8$ , or in interval notation, $(8,\infty)$

To find the range, consider the limits of the function as you approach either endpoint of the domain.

$\displaystyle\lim_{x\to8^+}\frac1{\sqrt{x-8}}=+\infty$
$\displaystyle\lim_{x\to\infty}\frac1{\sqrt{x-8}}=0$

Since $\dfrac1{\sqrt{x-8}}$ is positive everywhere, the range is $(0,\infty)$

3 0

3 years ago

For which values of a the system has at least one solution: x≤7 x≥a urgent pls help now

allochka39001 [22]

Answer:

We have the system:

x ≤ 7

x ≥ a

Now we want to find the possible values of a such that the system has, at least, one solution.

First, we should look at the value of a where the system has only one solution:

We can write the 2 sets as:

a ≤ x

x ≥ 7

So, writing both together:

a ≤ x ≤ 7

if a is larger than 7, we do not have solutions.

then a = 7 gives:

7 ≤ x ≤ 7

Here the only solution is 7.

Now, if a is smaller than 7, for example 5, we have:

5 ≤ x ≤ 7

Now x can take different values, so we have a lot of solutions.

Then the restrictions for a, such that the system has at least one solution, is:

a ≤ 7.

6 0

4 years ago