Answer:
Step-by-step explanation:
Joint variation has the equation
y = kxz
k is the constant of variation and needs to be solved for using the initial conditions, then filled in later to another equation related to the given info to solve for something else. We are given y = amount of oil used, x = distance traveled, z-squared is the speed. Our equation looks like this, to be exact:
Filling in with the initial conditions:
which gives us the
k = .0014166667
Now we need to find the amount of oil used, y, under other circumstances, but this time we have our k.
which gives us that the amount of oil used, when rounded to the tenths,
y = 24.0 barrels
It's a deal. Give me a question, and I'll give you an answer in units.
Step-by-step explanation:
Well, this is a function. In order to solve this, you need a v value. Once you get a v value, you can plug into into 6+v^2 and wala- you get your answer.
Example, lets say
v is 3
then
F(3) = 6 + 3^2
f(3) = 6 + 9
f(3) =15
Hope this helped
Answer: a,b, and c are the correct solutions
Step-by-step explanation:
You are substituting each (x,y) for the equation given. They must equal the same on both sides.
Answer: See below
Step-by-step explanation:
27. -(a-3)
28. (b-1)(b+3)
29. (c+4)(c+5)
30. d(d+5)
31. -(3/4)(2e-5)
Sorry - I don't have time to enter the details. Look for areas where the expressions can be factored in a manner that forms as many equivalent expressions in both the numerator and denominator.
For example: In problem 30:
(5d-20)/(d^2+d-20) * [??]/20d = 1/4
Factor:
<u>(5(d-4))</u> <u>d(d+5)</u> = 1/4
(d-4)(d+5<u>)</u> 20d
The (d-4), d+5, and d terms cancel, leaving
5/20 = 1/4
