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3 years ago

What's the answer to this

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

8 0

Answer:

m =24-8/4-2=16/2 y=4x

Step-by-step explanation:

m=24-8=16 =4-2=2

y= last number of x

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Solve: x + 6 = -11<br> May I please have help with this?!

klemol [59]

Answer:

x=-17

Step-by-step explanation:

subtract 6 from each side and simplify and you'll get -17

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2 years ago

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Using the graph of f(x) = log10x below, approximate the value of y in the equation 10y = 3.

Svetllana [295]

$f(x)=\log_{10}x \\ 10^y=3 \\ y=\log_{10}3=0.4771$

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3 years ago

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CHALLENGE PROBLEM Danny's Department Store advertises savings of

Oksanka [162]

Discount are used to reduce the costs of items

The percent paid to determine the advertisement is incorrect

<h3>How to determine the correct percentage</h3>

The initial prices are given as: $44.00 to $152.00

And the discount is: 45% to 51%

At a discount of 45%, the price of the items would be:

$Price = \$44.00 * (1 - 45\%)$

$Price = \$24.2$

$Price_2 = \$152.00 * (1 - 45\%)$

$Price_2 = \$83.6$

At a discount of 51%, the price of the items would be:

$Price = \$44.00 * (1 - 51\%)$

$Price = \$21.56$

$Price_2 = \$152.00 * (1 - 51\%)$

$Price_2 = \$74.48$

The calculates prices show that the percent paid to determine the advertisement is incorrect

Read more about discounts at:

brainly.com/question/23103804

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2 years ago

Radioactive Waste The rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt,

Dmitry_Shevchenko [17]

Answer:

$\displaystyle{\int^{\infty}_0 {50e^{-0.04t}}\, dt}=1250$

Step-by-step explanation:

Given:

$T =\displaystyle{\int^{\infty}_0 {Pe^{-kt}} \, dt}$

where,

T = total amount of waste

P = 50, the initial rate

k = 0.04

t = time

$T =\displaystyle{\int^{\infty}_0 {50e^{-0.04t}} \, dt}$

now we need to solve this integral!

$T =\displaystyle{50\int^{\infty}_0 {e^{-0.04t}} \, dt}$

$T = \left|50\left(\dfrac{e^{-0.04t}}{-0.04}\right)\right|^{\infty}_0$

$T = \left|-1250e^{-0.04t}\right|^{\infty}_0$

$T = (-1250e^{-0.04(\infty)})-(-1250e^{-0.04(0)})$

when any number has a power of negative infinity it is 0. because: $a^-{\infty} = \dfrac{1}{a^{\infty}} = \dfrac{1}{\infty} = 0$ , like something being divided by a very large number!

$T = (-1250(0))-(-1250e^0)$

$T = 1250$

this is the total amount of waste

6 0

3 years ago

Solve using quadratic formula. X^2-13x-48=0

agasfer [191]

I hope this helps you

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3 years ago

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