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kari74 [83]
3 years ago
12

What's the answer to this

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
8 0

Answer:

m =24-8/4-2=16/2 y=4x

Step-by-step explanation:

m=24-8=16 =4-2=2

y= last number of x

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The sum of 4 and 5 is subtracted from one-third of the difference of 40 and 4.​
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Sum of 4 and 5 → 4 + 5 = 9

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Questions attached as screenshot below:Please help me I need good explanations before final testI pay attention
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The acceleration of the particle is given by the formula mentioned below:

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Differentiate the position vector with respect to t.

\begin{gathered} \frac{ds(t)}{dt}=\frac{d}{dt}\sqrt[]{\mleft(t^3+1\mright)} \\ =-\frac{1}{2}(t^3+1)^{-\frac{1}{2}}\times3t^2 \\ =\frac{3}{2}\frac{t^2}{\sqrt{(t^3+1)}} \end{gathered}

Differentiate both sides of the obtained equation with respect to t.

\begin{gathered} \frac{d^2s(t)}{dx^2}=\frac{3}{2}(\frac{2t}{\sqrt[]{(t^3+1)}}+t^2(-\frac{3}{2})\times\frac{1}{(t^3+1)^{\frac{3}{2}}}) \\ =\frac{3t}{\sqrt[]{(t^3+1)}}-\frac{9}{4}\frac{t^2}{(t^3+1)^{\frac{3}{2}}} \end{gathered}

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\begin{gathered} a(t=1)=\frac{3}{\sqrt[]{2}}-\frac{9}{4\times2^{\frac{3}{2}}} \\ =1.32ft/sec^2 \end{gathered}

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\begin{gathered} s(0)=-23\times0+65 \\ =65 \end{gathered}

8 0
1 year ago
What’s the area of the figure shown below???
ozzi
The answer is 27 yards squared 
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3 years ago
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