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Schach [20]
2 years ago
12

Find the growth factor associated with the given growth rate. Growth rate = 6% *

Mathematics
2 answers:
arlik [135]2 years ago
8 0
I think it’s A or C but i would look up what’s the decimal of 6%!:)
SashulF [63]2 years ago
3 0
Well I changed it in to a decimal and got 0.06 so I think the answer is A
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Point A is at (6,-6) and point C is at(-6,-2). find the coordinates of B on AC so that AB= 3/4AC.
loris [4]

Answer:

B(-6, 0)

Step-by-step explanation:

You want to find B such that ...

(B -A) = (3/4)(C -A) . . . . the required distance relation

4(B -A) = 3(C -A) . . . . . . multiply by 4

4B = 3C +A . . . . . . . . . . add 4A, simplify

Now, we can solve for B and substitute the given coordinates:

B = (3C +A)/4 = (3(-6, -2) +(-6, 6))/4 = (-24, 0)/4 = (-6, 0)

The coordinates of point B are (-6, 0).

Hope it helped u if yes mark me BRAINLIEST!

Tysm!

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6 0
3 years ago
I WILL MAKE YOU BRAINLIEST EASY QUESTION
skelet666 [1.2K]

Answer:

D.)


/


Step-by-step explanation:


3 0
3 years ago
Read 2 more answers
If ab= 7x-6 and bc= 12-2x. Then what does ac equal?
ra1l [238]
Ab = (7x-6) →   b = (7x-6)/a   (1)

bc = (12-2x) → b = (12-2x)/c   (2)

Since (1) = (2) → (7x-6)/a = (12-2x)/c OR  a/c = (7x-6)/(12-2x)  (3)

Multiply  both numerators of (3) by the SQUARE of their  respective denominators;

(a*c²)/c = (7x-6)(12-2x)²/(12-2x)
Now simplify:

ac = (7x-6)(12x-2x)  or ac = -14x² + 96x - 72


4 0
3 years ago
At the beginning of each of her four years in college, Miranda took out a new Stafford loan. Each loan had a principal of $5,500
kaheart [24]

Answer:

D. $31,337.27

Step-by-step explanation:

We have that the initial amount of the loan is $5500.

Miranda took the loan for 4 years. So, the total present value is $5500×4 = $22,000.

The rate of interest on the loan is 7.5% i.e. 0.075 and it was for the duration of 10 years.

Also, it is given that the loan was compounded annually.

We have the formula as,

P=\frac{\frac{r}{n}\times PV}{1-(1+\frac{r}{n})^{-t\times n}}

i.e. PV=\frac{P\times [1-(1+\frac{r}{n})^{-t\times n}]}{\frac{r}{n}}

Substituting the values, we get,

i.e. PV=\frac{P\times [1-(1+\frac{0.075}{12})^{-10\times 12}]}{\frac{0.075}{12}}

i.e. 22000=\frac{P\times [1-(1+0.00625)^{-120}]}{0.00625}

i.e. 22000=\frac{P\times [1-(1.00625)^{-120}]}{0.00625}

i.e. 22000=\frac{P\times [1-0.4735]}{0.00625}

i.e. 22000=\frac{P\times 0.5265}{0.00625}

i.e. P=\frac{22000\times 0.00625}{0.5265}

i.e. P=\frac{137.5}{0.5265}

i.e. P=261.16

Thus, the total lifetime cost to pay of the loans compounded annually  = 261.16 × 120 = $31,339.2

Hence, the total cost close to the answer is $31,337.27

7 0
3 years ago
Read 2 more answers
if grant drove his car for 417 miles on 15 gallons of gas. how many miles per gallon does grants car get?
lara [203]

Answer:

27.8 per mile.

Step-by-step explanation:

417 divided by 15 equals 27.8 miles per gallon

miles/ gallon

/ = per

so

417/ 15

27.8 gallons

3 0
2 years ago
Read 2 more answers
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