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3 years ago

Find the distance between the points (-3, -6) and (5,9). Hint: Use the Pythagorean theorem.

Mathematics

1 answer:

Zinaida [17]3 years ago

4 0

Answer:

The distance between the points (-3, -6) and (5, 9) is 15 units.

Step-by-step explanation:

Given the points

(-3, -6)

(5, 9)

First, we need to find the distance between the two x-coordinates. For this, we need to count the distance from 0 to another point. Then we just add them together.

i.e.

-3 to get to 0 takes 3 units

0 to 5 takes 5 units

3+5=8 units

Just do the same for y-coordinate

From -6 to 0 takes 6 units

0 to 9 takes 9 units

6+9 = 15 units

Therefore, we get the base and height.

Now using the Pythagoras' Theorem to find the distance:

c² = 8² + 15²

c² = 289

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$c=\sqrt{289},\:c=-\sqrt{289}$

$c=17,\:c=-17$

As the distance can not be negative.

c = 15 units

Thus, the distance between the points (-3, -6) and (5, 9) is 15 units.

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Please will give brainliest and thanks

VMariaS [17]

Answer:

$- \frac{6}{7}p + \frac{1}{7}$

Step-by-step explanation:

Get rid of the parenthesis then combine like terms

8 0

3 years ago

A ball is thrown in the air from a platform that is 96 feet above ground level with an initial vertical velocity of 32 feet per

pishuonlain [190]

Answer:

y = -16 (x - 1)^2 + 112

The object lands on the ground in approximately 3.6s

Explanation:

The equation given is that of a parabola.

Now the maximum (local) point of a parabola is the vertex. Therefore, if we want to rewrite our function in the form that would be used to find the maximum height, then that form must be the vertex form of a parabola.

The vertex form of a parabola is

$y=a(t-h)^2+k$

where (h, k) is the vertex.

The only question is, what is the vertex for our function h(t)?

Remember that if we have an equation of the form

$y=ax^2+bx+c$

then the x-coordinate of the vertex is

$h=-\frac{b}{2a}$

Now in our case b = 32 and a = -16; therefore,

$h=\frac{-32}{2(16)}=1$

We've found the value of the x-coordinate of the vertex. What about the y-coordinate? To get the y-coordinate, we put x = 1 into h(t) and get

$k=-16(1)+32(1)+96=112$

Hence, the y-coordindate is k = 112.

Therefore, the vertex of the parabola is (1, 112).

With the coordinates of the vertex in hand, we now write the equation of the parabola in vertex form.

$h(t)=a(t-1)^2+112$

The only problem is that we don't know what the value of a is. How do we find a?

Note that the point (0, 96) lies on the parabola. In other words,

$h(0)=-16(0)^2+32(0)+96=96$

Therefore, the vertex form of the parabola must also contain the point (0, 96).

Putting in t = 0, h = 96 into the vertex form gives

$96=a(0-1)^2+112$ $96=a+112$

subtracting 112 from both sides gives

$a=-16$

With the value of a in hand, we can finally write the equation of the parabola on vertex form.

$\boxed{h\mleft(t\mright)=-16\left(t-1\right)^2+112.}$

Now when does the object hit the ground? In other words, for what value of t is h(t) = 0? To find out we just have to solve the following for t.

$h(t)=0.$

We could either use h(t) = -16t^2 + 32t + 96 or the h(t) = -16(t - 1)^2 + 112 for the above equation. But it turns out, the vertex form is more convenient.

Thus we solve,

$-16\left(t-1\right)^2+112=0$

Now subtracting 112 from both sides gives

$-16(t-1)^2=-112$

Dividing both sides by -16 gives

$(t-1)^2=\frac{-112}{-16}$ $(t-1)^2=7$

taking the square root of both sides gives

$t-1=\pm\sqrt{7}$

adding 1 to both sides gives

$t=\pm\sqrt{7}+1$

Hence, the two solutions we get are

$t=\sqrt{7}+1=3.6$ $t=-\sqrt{7}+1=-1.6$

Now since time cannot take a negative value, we discard the second solution and say that t = 3.6 is our valid solution.

Therefore, it takes about 3.6 seconds for the object to hit the ground.

3 0

1 year ago

Johnny will work 15 hours a week during the 36 week school year, and 40 hours a

Naddika [18.5K]

Answer:

He will save 590 dollars by the end of the year

7 0

3 years ago

If two pounds of meat will serve 5 people how many pounds will be needed to serve 13 people

miv72 [106K]

The answer is 5.2 pounds of meat. To find this just divide the number of people by what the information you have about servings. 13/5=2.6(number of sets), then you multiply that by how many pounds are in each set. 2.6 sets* 2 pounds per set= 5.2 pounds.
I hope this helped!

4 0

3 years ago

Anyone wanna help?please

timama [110]

$\large\underline{\underline{\red{\rm\blue{\longmapsto} Step-by-step\: Explanation:-}}}$

Given to points to us are :-

( 3 , -6 )
( -1 , -8 )

( As these are plotted on graph with yellow dots .)

Now , we can use Distance Formula , which is :-

$\boxed{\pink{\tt Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}}$

Here ,

x1 = 3 .
x2 = -1.
y1 = (-6)
y2 = (-8).

<u>→ Substituting the respective values , </u>

⇒ Distance = √ [ { 3 - (-1)}² + { -6 -(-8)²} ] .

⇒ Distance = √ (3+1)² + (8-6)²

⇒ Distance = √ 4² + 2²

⇒ Distance = √ 16 + 4

⇒ Distance = √20 = √4 × √5

⇒ Distance = 4√5units .

<u>Hence the distance between two points is 4√5u.</u>

3 0

3 years ago