Answer:
<em>99.93%</em>
Step-by-step explanation:
<u>Probability of Independent Events</u>
Given the probability of success of each detector is 0.84 independently of the others, their combined success/failure probability can be computed with the product rule.
We can calculate the required probability by using the binomial distribution, but it's easier to calculate the probability of the negated event an subtract from 1.
We want to know the probability that a least one of the 4 systems detects the occurrence of theft. That probability is the sum of the probabilities that one of them, two of them, three of them or all of them succeed. The negated event is that NONE of them actually detects the theft. Being p the individual probability of success, p=0.84. Being q the probability of failure, q=0.16.
The probability that none of the systems detect the theft is

Thus, the probability that at least one of the systems detect the theft is

That means a 99.93%
ANSWER:
x = 10 / 3
y = 0
STEP-BY-STEP EXPLANATION:
We will be using simultaneous equations to solve this problem. Let's first establish the two equations which we will be using.
Equation No. 1 -
- 6x - 14y = - 20
Equation No. 2 -
- 3x - 7y = - 10
First, we will make ( x ) the subject in the first equation and simplify accordingly.
Equation No. 1 -
- 6x - 14y = - 20
- 6x = - 20 + 14y
x = ( - 20 + 14y ) / - 6
x = ( - 10 + 7y ) / - 3
From this, we will make ( y ) the subject in the second equation and substitute the value of ( x ) from the first equation into the second equation to solve for ( y ) accordingly.
Equation No. 2 -
- 3x - 7y = - 10
- 7y = - 10 + 3x
- 7y = - 10 + 3 [ ( - 10 + 7y ) / - 3 ]
- 7y = - 10 + [ ( - 30 + 21y ) / - 3 ]
- 7y = - 10 + ( 10 - 7y )
- 7y = - 7y
- 7y + 7y = 0
0y = 0
y = 0
Using this, we will substitute the value of ( y ) from the second equation into the first equation to solve for ( x ) accordingly.
x = ( - 10 + 7y ) / - 3
x = [ - 10 + 7 ( 0 ) ] / - 3
x = [ - 10 + 0 ] / - 3
x = - 10 / - 3
x = 10 / 3
In the second fraction, factorize the denominator:

Then we have, as long as
,

which you could also write as

Answer: A Hexagon
Step-by-step explanation: