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777dan777 [17]
2 years ago
12

Can someone pls help me with this thank you very much :)​

Mathematics
1 answer:
liberstina [14]2 years ago
7 0

Answer:

Step-by-step explanation:

M O N K I E

You might be interested in
Given ab/bc = fe/ed find ac
zubka84 [21]
Well, you can cancel out the b and e, so a/c = f/d.

Then you cancel out a on the left side of the equation by multiplying both sides by 1/a which then gives you c = f/ad.

Hope this helps!
6 0
2 years ago
In a small town 68% of the people owned television 72% on radio and 12% owned neither television nor radio (1)represent the info
Naddika [18.5K]

Answer:

1.)

The Venn diagram is in the attachment

2).

percentage of the population that owns only television== 16%

Step-by-step explanation:

The Venn diagram Is represented in the attached photo.

Let's call The total people x

X = people that own only television+ people that own only radio+ people that own both television and radio+ people that own neither the two.

X= (0.68x -y) +(y) +(0.72x-y)+(0.12x)

X= 0.68x-y+y+0.72x-y+0.12x

X= 1.52x-y

Y= 1.52x-x

Y= 0.52x

People that own both= 52%

people that own only television

= (0.68x -y)

= 0.68x-0.52x

= 0.16x

percentage of the population that owns only television= 0.16*100

percentage of the population that owns only television= 16%

4 0
3 years ago
What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?
DENIUS [597]

Answer:

i. 9

ii. 14

iii. 405

iv. \frac{n(n-3)}{2}

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

\frac{n(n-3)}{2}

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = \frac{6(6-3)}{2}

                                   = \frac{18}{2}

                                   = 9

The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = \frac{7(7-3)}{2}

                                   = \frac{28}{2}

                                   = 14

The number of diagonals in a heptagon is 14.

iii. For a 30-gon;

number of diagonals = \frac{30(30-3)}{2}

                                          = \frac{810}{2}

                                         = 405

The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = \frac{n(n-3)}{2}

The number of diagonals in a n-gon is \frac{n(n-3)}{2}

7 0
3 years ago
A rectangle has sides that measure x + 1/4
maksim [4K]

Answer:

6x + 5/6

Step-by-step explanation:

2(x + 1/4) + 2(2x + 1/3)

2x + 1/2 + 4x + 2/3

6x + 5/6

6 0
2 years ago
Is 16.263548952347... a rational<br> number and why?
anzhelika [568]

Answer: no it is not

Step-by-step explanation: any number that repeats forever cannot be written as a rational way or a fraction. So it is not rational.

8 0
3 years ago
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