Question

The equation of the line passing through the points (3, 16) and (5, 10) can be expressed as y = mx + b. Give the value of b

Answer 1

we are given two points as

(3, 16) and (5, 10)

firstly , we will find slope

slope is m

so, we can use formula

$m=\frac{y_2-y_1}{x_2-x_1}$

now, we can plug points

$m=\frac{10-16}{5-3}$

$m=\frac{-6}{2}$

$m=-3$

we can plug it in y=mx+b

we get

$y=-3x+b$

now, we can select any one points

and find b

(3,16)

x=3 and y=16

$16=-3*3+b$

we can find b

$b=25$

now, we can plug back b

and we get

$y=-3x+25$

so, equation is

$y=-3x+25$

and

$b=25$...............Answer