Answer:
10472. 4 ft
Step-by-step explanation:
Let the height of the plane above the helicopter be "h"
We have a right triangle where the side opposite the 71 degree angle = h and the side adjacent to this angle = 3055
So we can use the tangent here
tan (71) = h / 3055 multiply both sides by 3055
3055 * tan (71) = h ≈ 8872.4 ft
So.......the total altitude of the plane is
1600 + 8872.4 =
10472. 4 ft
Answer: r=7x-1/8
Step-by-step explanation:
2(4r+3)=7x/2+5/2
4r+3=7x+5/2
4r+3-3=7x+5/2 -3
4r=7x+5/2 -3
4r/4= 7x-5/2/4 -3/4
r=7x-1/8
Answer:
Area of a trapezoid = ½(a + b)h, where a and b are the lengths of the parallel sides and h is its height.
From your information 20 = ½(2z + 3 + 6z – 1)z = ½(8z + 2)z = z(4z + 1)
Solve 20 = 4z² + z which is 0 = 4z² + z – 20 using the quadratic formula
Step-by-step explanation:
Answer:
Step-by-step explanation:
All the masses here are based on the main mass of the sand. So we will call sand "x". If there is two times as much cement as sand, then cement is 2x; if there is three times as much stone as sand, then stone is 3x. All of these added together equal a mass of 600 kg:
x + 2x + 3x = 600 so
6x = 600 and
x = 100 kg
There are 100 kg of sand. That means that there is 200 kg of cement and 300 kg of stone
