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3 years ago

How does one do this? may someone teach me how to calculate and solve this problem please, thanks.

Mathematics

2 answers:

Naddika [18.5K]3 years ago

7 0

Answer:

x=1

Step-by-step explanation:

So we are talking about parabola functions.

All parabolas (even if they aren't functions) have their axis of symmetry going through their vertex.

For parabola functions, your axis of symmetry is x=a number.

The "a number" part will be the x-coordinate of the vertex.

The axis of symmetry is x=1.

Margaret [11]3 years ago

3 0

Answer:

x=1

Step-by-step explanation:

The vertex of a parabola is the minimum or maximum of the parabola.

This is the line where the parabola makes a mirror image.

Assuming the equation for the parabola is ( since this is a function)

y= a(x-h)^2 +k

where (h,k) is the vertex

Then x=h is the axis of symmetry

y = a(x-1)^2+5

when we substitute the vertex into the equation

The axis of symmetry is x=1

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You draw five cards at random from a standard deck of 52 playing cards. What is the probability that the hand drawn is a full ho

Stels [109]

Answer:

The probability that the hand drawn is a full house is 0.00144.

Step-by-step explanation:

In a full house we have a hand that consists of two of one kind and three of another kind, i.e 5 cards are selected.

The number of ways of selecting 5 cards from 52 cards is:

${52\choose 5} = \frac{52!}{5!(52-5)!} \\=\frac{52!}{5!\times47!} \\=2598960$

In a deck of 52 cards there are 13 kind of cards, namely{K, Q, J, A, 2, 3, 4, 5, 6, 7, 8, 9, 10}.

Two kinds can be selected in, ${13\choose 2}=\frac{13!}{2!\times(13-2)!} =\frac{13!}{2!\times11!} =78$ ways

One of the two kinds can be selected for 3 cards combination in ${2\choose 1} = 2$ ways.

There are 4 cards of each kind.

So 3 cards combination can be selected from any of the two kinds in ${4\choose 3} =\frac{4!}{3!(4-3)!} =4$ ways.

And 2 cards combination can be selected from any of the two kinds in ${4\choose 2} =\frac{4!}{2!(4-2)!} =6$ ways.

Thus, total number of ways to select a full house is:

${13\choose 2}\times{2\choose 1}\times{4\choose 3}\times{4\choose 2}\\=78\times2\times4\times6\\=3744$

The probability that the hand drawn is a full house is:

$\frac{Number\ of\ ways\ of\ Drawing\ a\ Full\ house)}{Number\ of\ ways\ of\ Selecting\ 5\ cards } =\frac{3744}{2598960} =0.00144$

Thus, the probability of playing a full house is 0.00144.

6 0

3 years ago

Write the number that can be shown with this many hundreds tens and ones 1 2 18

NISA [10]

Maybe is 2181 the biggest

6 0

3 years ago

Lucas started off with $10.00. he gave away 20% of his money to his sister, and 30% of the remainder of his money to his brother

Korolek [52]

Answer:

5.60

Step-by-step explanation:

20% of 10 = 2 he gave 2 dollars to his sis

2 - 10 = 8 now lucas has 8 dollars

30% of 8 = 2.4 he gave 2.40 dollars to his bro

2.4 - 8 = 5.6

now he has 5 dollars and 60 cents

give me brainlest pls pls pls :>

6 0

3 years ago

Read 2 more answers

I’ll really appreciate it if you help me out on this on .

dybincka [34]

Answer:

2(5) + 2x

Step-by-step explanation:

The equation to find perimeter is P = 2L + 2W ( P = L + L + W + W )

Since this question is asking for an expression to solve for the perimeter of this particular rectangle, I would say 2(5) + 2x. A simpler expression could be 10 + 2x.

7 0

2 years ago

Can someone please help me?

storchak [24]

5lbs=8.25
/5 /5
1lbs=1.65

6 0

3 years ago

How does one do this? may someone teach me how to calculate and solve this problem please, thanks.​

How does one do this? may someone teach me how to calculate and solve this problem please, thanks.