Answer:
202 °C
Explanation:
From the question given above, the following data were obtained:
Initial temperature (T₁) = 90 °C
Initial volume (V₁) = 15.5 L
Final volume (V₂) = 20.3 L
Final temperature (T₂) =?
Next, we shall convert 90 °C to Kelvin temperature. This is illustrated below:
T(K) = T(°C) + 273
Initial temperature (T₁) = 90 °C
Initial temperature (T₁) = 90 °C + 273
Initial temperature (T₁) = 363 K
Next, we shall determine the final temperature.
Initial temperature (T₁) = 363 K
Initial volume (V₁) = 15.5 L
Final volume (V₂) = 20.3 L
Final temperature (T₂) =?
V₁ / T₁ = V₂ / T₂
15.5 / 363 = 20.3 / T₂
Cross multiply
15.5 × T₂ = 363 × 20.3
15.5 × T₂ = 7368.9
Divide both side by 15.5
T₂ = 7368.9 / 15.5
T₂ ≈ 475 K
Finally, we shall convert 475 K to celsius temperature. This is illustrated below:
T(°C) = T(K) – 273
T₂ = 475 – 273
T₂ = 202 °C
Thus, the new temperature of the gas is 202 °C
