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uranmaximum [27]
3 years ago
7

List five household items that contain the same chemicals as cigarettes.

Chemistry
1 answer:
WITCHER [35]3 years ago
5 0

<em>Five household items that </em><em>contain</em><em> the same chemicals as cigarettes :</em><em>-</em>

  1. <em>Perfume</em>
  2. <em>Household</em><em> </em><em>cleaning</em><em> </em><em>products</em>
  3. <em>Beauty</em><em> </em><em>Products</em>
  4. <em>Sunscreen</em>
  5. <em>Water</em><em> </em><em>bottles</em>

<em>They</em><em> </em><em>contain</em><em> </em><em>toxic</em><em> </em><em>substances</em><em>!</em>

<em>hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>!</em>

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Meiosis happens in the major cells of multicellular organisms. true or false
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Answer:

True.

Explanation:

Btw ya spelled mitosis wrong...

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3 years ago
What do you understand by<br> eclipse?<br>​
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6 0
3 years ago
how many moles of solute are contained in 500.00 milliliter solution that has a concentration of 0.35M
igomit [66]

1.75 moles of Solute or 1.75n.

To find this, you'll need to use the molarity equation which is M = \frac{n}{v}

List the given items to organize better:

M (Molarity) = .35

V (Volume) = 5L [must always be in Liters]

n (Moles) = ?

Now, for the equation, substitute the variables with the given numbers:

.35 = \frac{n}{5}

Isolate the variable by multiplying the volume, 5, onto both sides. This will give you the answer of:

1.75 = n

Hope this helps!

6 0
3 years ago
Which statement best describes nuclear binding energy
tia_tia [17]
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6 0
4 years ago
Please answer these about Charles law
NNADVOKAT [17]

Answer:

1. V2.

2. 299K.

3. 451K

4. 0.25 x 451 = V2 x 299

Explanation:

1. The data obtained from the question include:

Initial volume (V1) = 0.25mL

Initial temperature (T1) = 26°C

Final temperature (T2) = 178°C

Final volume (V2) =.?

2. Conversion from celsius to Kelvin temperature.

T(K) = T (°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K

3. Conversion from celsius to Kelvin temperature.

T(K) = T (°C) + 273

Final temperature (T2) = 178°C

Final temperature (T1) = 178°C + 273 = 451K

4. Initial volume (V1) = 0.25mL

Initial temperature (T1) = 299K

Final temperature (T2) = 451K

Final volume (V2) =.?

V1 x T2 = V2 x T1

0.25 x 451 = V2 x 299

6 0
4 years ago
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