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2 years ago

A solution has a pOH of 8.7 so what is the pH of the solution? Is the solution acidic, basic, or neutral?

2 answers:

5 0

PH + pOH = 14

pH = 14 - pOH

pH = 14 - 8.7

pH = 5,3

This solution is <u>acidic</u>.

If pH<7 - acidic
If pH=7 - neutral
If pH>7 - basic

Alona [7]2 years ago

5 0

pOH scale is used to determine the basicity of a solution

pH scale is used to determine the acidity of a solution

pH and pOH are related in the following formula

pH + pOH = 14

once pOH is known we can calculate pH

pOH = 8.7

pH = 14 - 8.7

pH = 5.3

pH of the solution is 5.3

when pH is less than 7 the solution is said to be acidic

when pH is equal to 7 then solution is neutral

when pH is more than 7 then solution is basic

the pH of the solution here is 5.3 which is less than 7, therefore solution is acidic

acidic solution with pH of 5.3

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Suppose that 25.0 mL of 0.10 M CH3COOH (aq) is titrated with 0.10 M NaOH (aq). What is the pH after the addition of 10.0 mL of 0

olya-2409 [2.1K]

Answer:

$pH=-1.37$

Explanation:

We are given that 25 mL of 0.10 M $CH_3COOH$ is titrated with 0.10 M NaOH(aq).

We have to find the pH of solution

Volume of $CH_3COOH=25mL=0.025 L$

Volume of NaoH=0.01 L

Volume of solution =25 +10=35 mL= $\frac{35}{1000}=0.035 L$

Because 1 L=1000 mL

Molarity of NaOH=Concentration OH-=0.10M

Concentration of H+= Molarity of $CH_3COOH$ =0.10 M

Number of moles of H+=Molarity multiply by volume of given acid

Number of moles of H+= $0.10\times 0.025$ =0.0025 moles

Number of moles of $OH^-=0.10\times 0.01$ =0.001mole

Number of moles of H+ remaining after adding 10 mL base = 0.0025-0.001=0.0015 moles

Concentration of H+= $\frac{0.0015}{0.035}=4.28\times 10^{-2} m/L$

pH=-log [H+]=-log [4.28 $\times 10^{-2}$ ]=-log4.28+2 log 10=-0.631+2

$pH=-1.37$

6 0

2 years ago

3. What agency tracks the activities of typhoon that enters PAR?

SOVA2 [1]

Answer:

D. Philippine Atmospheric, Geophysical and Astronomical Services

Administration (PAGASA)

Explanation:

4.C. 62.0 kph

5 0

2 years ago

6.0 mol Al reacts with 4.0 mol O2 to form Al2O3.

Tema [17]

Answer:

3.0 moles Al₂O₃

Explanation:

We do not know which of the reactants is the limiting reactant. Therefore, you need to convert both of the given mole values into the product. This can be done using the mole-to-mole ratio made up of the balanced equation coefficients.

4 Al + 3 O₂ -----> 2 Al₂O₃

6.0 moles Al 2 moles Al₂O₃
---------------------- x ------------------------- = 3.0 moles Al₂O₃
4 moles Al

4.0 moles O₂ 2 moles Al₂O₃
---------------------- x ------------------------- = 2.7 moles Al₂O₃
3 moles O₂

As you can see, O₂ produces the smaller amount of product. This means O₂ is the limiting reactant. Remember, the limiting reactant is the reactant which runs out before the other reactant(s) are completely reacted. As such, the actual amount of Al₂O₃ produced is 2.7 moles.

However, since this problem is directly addressing how much Al₂O₃ is produced from Al, the answer you most likely are looking for is 3.0 moles Al₂O₃.

6 0

11 months ago

The answer to this question

Ulleksa [173]

Hey there!

Oxygen needs two bonds to have a valence orbital of s²p⁶.

In a hexanal molecule, oxygen has a double bond with one carbon atom.

A double bond is when two pairs of electrons are being shared.

So your answer is b. 2.

Hope this helps!

7 0

3 years ago