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jek_recluse [69]
3 years ago
11

A solution has a pOH of 8.7 so what is the pH of the solution? Is the solution acidic, basic, or neutral?

Chemistry
2 answers:
RSB [31]3 years ago
5 0
PH + pOH = 14

pH = 14 - pOH

pH = 14 - 8.7

pH = 5,3

This solution is <u>acidic</u>.

If pH<7 - acidic
If pH=7 - neutral
If pH>7 - basic
Alona [7]3 years ago
5 0

pOH scale is used to determine the basicity of a solution

pH scale is used to determine the acidity of a solution

pH and pOH are related in the following formula

pH + pOH = 14

once pOH is known we can calculate pH

pOH = 8.7

pH = 14 - 8.7

pH = 5.3


pH of the solution is 5.3


when pH is less than 7 the solution is said to be acidic

when pH is equal to 7 then solution is neutral

when pH is more than 7 then solution is basic

the pH of the solution here is 5.3 which is less than 7, therefore solution is acidic

acidic solution with pH of 5.3

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Gasoline and kerosene (specific gravity 0.820) are blended to obtain a mixture with a specific gravity of 0.770. Calculate the v
Dmitrij [34]

Answer:

The volumetric ratio is 0,71

Explanation:

Let's begin with the equation:

Db = Mb/Vb (1)

Where:

Db: Blend Density, Mb: Blend Mass and Vb: Blend Volume

And we know: Vb = Vg + Vk (2)

Where:

Vg: Gasoline Volume and Vk: Kerosene Volume

Therefore replacing (2) into (1):

Db = (Mg + Mk) / (Vg + Vk)

Db = (Dg * Vg + Dk * Vk)/(Vg + Vk) (3)

Where:

Dg: Gasoline Density and Dk: Kerosene Density

The specific gravity is defined as:

SG = Substance Density / Reference Density

Therefore:

Db = SGb * Dref\\Dg = SGg * Dref\\Dk = SGk * Dref

Where:

Dref: Reference Density

SGb: Blend Specific Gravity

SGg: Gasoline Specific Gravity (which is 0.7 approximately)

SGk: Kerosene Specific Gravity

Replacing these equations into (3) we get:

SGb * Dref = (SGg * Dref * Vg + SGk * Dref * Vk)/(Vg + Vk)

SGb * Dref = Dref * (SGg * Vg + SGk * Vk)/(Vg + Vk)

SGb = (SGg * Vg + SGk * Vk)/(Vg + Vk)

SGb * (Vg + Vk) = SGg * Vg + SGk * Vk

SGb * Vg + SGb* Vk = SGg * Vg + SGk * Vk

Replacing with the Specific Gravity data, we obtain:

0.77 * Vg + 0.77 * Vk = 0.7 * Vg + 0.82 * Vk

0.77 * Vg - 0.7 * Vg = 0.82 * Vk - 0.77 * Vk

0.07 * Vg = 0.05 * Vk

Vg/Vk = 0.05/0.07

Vg/Vk = 0.71

8 0
2 years ago
Use the periodic table and example bond table to answer the question.
lyudmila [28]

In keeping with the general trends, K-Br will have the smallest bond energy. The bond energy refers to the energy that keeps the atoms in a bond together.

<h3>What is bond energy?</h3>

Bond energy is the energy that is required to hold atoms together in a bond. This energy must also be supplied when the atoms are to be separated.

We have the bond energies of each of the bons in the question, we have to note that the the smallest value of bond energy is Na-Br hence in keeping with the general trends, K-Br will have the smallest bond energy.

Learn more about bond energies: brainly.com/question/14842720?

7 0
1 year ago
In your discussion consider a SN2 reaction mechanism concept. Propose a modification of experimental procedure that would improv
Hitman42 [59]

Answer:

Here's what I get  

Explanation:

You may have done a Williamson synthesis of guaifenesin by reacting guaiacol with 3-chloropropane-1,2-diol.

A. Mechanism

Step 1

NaOH converts guaiacol into a phenoxide ion.

Step 2

The phenoxide acts as the nucleophile in an SN2 reaction to displace the Cl from the alkyl halide.

B. Improve the yield

You probably carried out the reaction in ethanol solution — a polar protic solvent.

You might try doing the reaction in a polar aprotic solvent— perhaps DMSO.

A polar aprotic solvent does not hydrogen bond to nucleophiles, so they become stronger.

C. Another method of ether synthesis —dehydration of alcohols

Sulfuric acid catalyzes the conversion of primary alcohols to ethers.

This is also a nucleophilic displacement reaction.

Protonation of the OH converts it into a better leaving group.

Attack by a second molecule of alcohol forms the protonated ether.

A molecule of water then removes the proton.

6 0
3 years ago
Hess’s law
Delvig [45]

From the statement of Hess' law, the enthalpy of the reaction A---> C is +90 kJ

<h3>What is Hess' law?</h3>

Hess' law of constant heat summation states that for a multistep reaction, the standard enthalpy of reaction is always constant and is independent of the pathway or intermediate routes taken.

From Hess' law, the enthalpy change for the reaction A ----> C is calculated as follows:

A---> C = A ---> B + B ---> C

ΔH of A---> C = 30 kJ + 60 kJ

ΔH = 90 kJ

Therefore, the enthalpy of the reaction A---> C is +90 kJ

The above reaction A---> C can be shown in the enthalpy diagram below:

A -------------------> C (ΔH = +90 kJ)

\ /

\ / (ΔH = +60 kJ)

(ΔH = +30 J) \ /

> B

Learn more about enthalpy and Hess law at: brainly.com/question/9328637

8 0
2 years ago
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Nataliya [291]
___AlBr3 + ___K -> ___KBr + ___ Al

1 AlBr3 + 3K -> 3KBr + 1 Al

hope this helps............
6 0
3 years ago
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