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2 years ago

Simplify: 3(9+3⋅8)−23

Mathematics

2 answers:

Artyom0805 [142]2 years ago

4 0

Answer:

15.4

Step-by-step explanation:

3(9+3⋅8)−23

3(12.8)-23

38.4-23

15.4

So the answer is15.4

Lena [83]2 years ago

3 0

Answer:

Step-by-step explanation:

3(9+24)-23

27+72-23

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Need help please assist me find the area of a regular hexagon

garri49 [273]

Answer:

The area of the regular hexagon is $166.3\ units^{2}$

Step-by-step explanation:

we know that

The area of a regular hexagon can be divided into 6 equilateral triangles

step 1

Find the area of one equilateral triangle

$A=\frac{1}{2}(b)(h)$

we have

$b=r=8\ units$

$h=4\sqrt{3}\ units$ ----> is the apothem

substitute

$A=\frac{1}{2}(8)(4\sqrt{3})$

$A=16\sqrt{3}\ units^{2}$

step 2

Find the area of 6 equilateral triangles

$A=(6)16\sqrt{3}=96\sqrt{3}=166.3\ units^{2}$

7 0

2 years ago

What IS 20 divided by 13 ?

goldenfox [79]

$Solution,\mathrm{Convert\:improper\:fractions\:to\:mixed\:numbers}:\quad \frac{20}{13}=1\frac{7}{13}$

$Steps:$

$\frac{20}{13}$

$\mathrm{Long\:Division}\:\frac{20}{13}:\quad 1\quad \mathrm{Remainder}\quad \:7$

$Convert\:to\:mixed\:number:\:Quotient\frac{Remainder}{Divisor},\\\frac{20}{13}=1\frac{7}{13}$

$Hope\: This\: Helps!!!$

4 0

3 years ago

Read 2 more answers

How much heat is released when 12. 0 grams of helium gas condense at 2. 17 K? The latent heat of vaporization of helium is 21 J/

aleksandr82 [10.1K]

The amount of heat released when 12.0g of helium gas condense at 2.17 K is; -250 J

The latent heat of vapourization of a substance is the amount of heat required to effect a change of state of the substance from liquid to gaseous state.

However, since we are required to determine heat released when the helium gas condenses.

The heat of condensation per gram is; -21 J/g.

Therefore, for 12grams, the heat of condensation released is; 12 × -21 = -252 J.

Approximately, -250J.