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love history [14]
2 years ago
8

You roll a 6-sided die. What is P(not odd)? Write your answer as a percentage.

Mathematics
1 answer:
tester [92]2 years ago
7 0

Answer:

\boxed{\textsf{ Hence the percentage probability of getting a not odd is \textbf{ 50\% }.}}

Step-by-step explanation:

Given that we roll a 6 sided dice . We need to find the probability that the outcome is not a odd number . So , when we roll a dice then the possible outcomes are ,

\sf\implies Sample\ space = \{ 1,2,3,4,5,6 \}

And the total number of possible outcomes is 6 . That is ,

\sf\implies n(Sample \ space )= 6

Now the total number of non odd numbers that is even numbers is 3 ( 2 , 4 & 6) .

\sf\implies n(Outcomes_{(even)})= 3

Now , lets use the formula of Probability that is ,

<u>Probability</u><u> </u><u>:</u><u>-</u>

\qquad\boxed{\boxed{\sf P = \dfrac{Total \ number \ of \ favourable\ outcomes }{Total \ number \ of \ possible\ outcomes }}}

<u>Now </u><u>pu</u><u>t</u><u> </u><u>on </u><u>the </u><u>respective</u><u> </u><u>values</u><u> </u><u>:</u><u>-</u>

\sf\implies P( getting\ a \ not \ odd ) =  \dfrac{Total \ number \ of \ favourable\ outcomes }{Total \ number \ of \ possible\ outcomes } \\\\\sf\implies P( getting\ a \ not \ odd ) =\dfrac{3}{6} \\\\\sf\implies \boxed{\sf P( getting\ a \ not \ odd ) = \dfrac{1}{2} }

\rule{200}2

<u>Expressing </u><u>the </u><u>probability</u><u> </u><u>as </u><u>percentage</u><u> </u><u>:</u><u>-</u>

\sf\implies \% \ of \ getting \ non \ odd = Probability \times 100 \\\\\sf\implies \% \ of \ getting \ non \ odd = \dfrac{1}{2}\times 100 \\\\\sf\implies \boxed{\pink{\frak{ \% \ of \ getting \ non \ odd = 50\%}}}

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