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topjm [15]
3 years ago
9

I just need to know which one works! Plz help urgent!

Mathematics
2 answers:
ira [324]3 years ago
7 0
They are all rational
Naya [18.7K]3 years ago
3 0
(00) (12) (48) is rational
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Find the area of the rhombus. d1 = 14 m; d2 = 18 m The area of the rhombus is ? m2.
xxTIMURxx [149]

<u><em>Answer:</em></u>

Area of rhombus = 126 m²

<u><em>Explanation:</em></u>

<u>We are given that the two diagonals of the rhombus are:</u>

D₁ = 14 meters and D₂ = 18 meters

<u>The area of the rhombus using its diagonals can be calculated using the following rule:</u>

Area = \frac{D_1 * D_2}{2}

<u>Substitute with the given values to get the area as follows:</u>

Area = \frac{14*18}{2}=126 m^2

Hope this helps :)

8 0
2 years ago
Read 2 more answers
Given that f(x)=x^2-4x -3 and g(x)=x+3/4 solve for f(g(x)) when x=9
SSSSS [86.1K]

Answer:

f(g(9)) = 945/16

Step-by-step explanation:

To find f(g(x)), you have to substitute g(x) wherever there is an x in f(x).

g(x) = x + 3/4

f(x) = x² - 4x - 3

f(g(x)) = (x + 3/4)² - 4(x + 3/4) - 3

f(g(x)) = x² + 3/2x + 9/16 - 4x + 3 - 3

f(g(x)) = x² - 5/2x + 9/16 + 3 - 3

f(g(x)) = x² - 5/2x + 9/16

Now, put a 9 wherever there is an x in f(g(x)).

f(g(9)) = (9)² - 5/2(9) + 9/16

f(g(9)) = 81 - 5/2(9) + 9/16

f(g(9)) = 81 - 45/2 + 9/16

f(g(9)) = 117/2 + 9/16

f(g(9)) = 945/16

7 0
3 years ago
What are the odds u multiply incorrect numbers and get it right
zheka24 [161]

Answer:

Very little.

Step-by-step explanation:

If you have 1x1=1, and change a number, there is no way that you will get the answer right to be 1.

4 0
3 years ago
If a gas tank of a large truck holds 64 gallons of gas if the tank is 5/8 full how many gallons of gas is in truck
den301095 [7]
Find 5/8 of full
find 5/8 of 64
5/8 times 64/1=320/8=160/4=80/2=40
answer is 40 gallons in the trick right now
4 0
3 years ago
5. Find the general solution to y'''-y''+4y'-4y = 0
CaHeK987 [17]

For any equation,

a_ny^(n)+\dots+a_1y'+a_0y=0

assume solution of a form, e^{yt}

Which leads to,

(e^{yt})'''-(e^{yt})''+4(e^{yt})'-4e^{yt}=0

Simplify to,

e^{yt}(y^3-y^2+4y-4)=0

Then find solutions,

\underline{y_1=1}, \underline{y_2=2i}, \underline{y_3=-2i}

For non repeated real root y, we have a form of,

y_1=c_1e^t

Following up,

For two non repeated complex roots y_2\neq y_3 where,

y_2=a+bi

and,

y_3=a-bi

the general solution has a form of,

y=e^{at}(c_2\cos(bt)+c_3\sin(bt))

Or in this case,

y=e^0(c_2\cos(2t)+c_3\sin(2t))

Now we just refine and get,

\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}

Hope this helps.

r3t40

5 0
3 years ago
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