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2 years ago

Suppose you are given two quadrilaterals, ABCD EFGH. If the similarity ratio of ABCD to EFGH is 4:3, and it EH =

Mathematics

2 answers:

serious [3.7K]2 years ago

8 0

Step-by-step explanation:

ABCD : EFGH = 4 : 3

Therefore AD : EH is also 4 : 3.

We are given that EH = 60,

Hence AD : (60) = 4 : 3, AD = 80. (D)

Ilia_Sergeevich [38]2 years ago

7 0

Answer:

Step-by-step explanation:

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bagirrra123 [75]

Answer:

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Step-by-step explanation:

1 129

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2 2

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3 years ago

Add one and one tenths equals three and one half

navik [9.2K]

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3 years ago

Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En

Sergio [31]

Answer:

$\bold{cot(t) =\dfrac{12}{5}}$

Step-by-step explanation:

Given that:

$Cosec (t) = -\frac{13}5$

for $\pi < t < \frac{3 \pi}2$

That means, angle $t$ is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

$cosec^2\theta -cot^2\theta =1$

here, $\theta =t$

So, $cosec^2t-cot^2t=1$

$\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}$

But, angle $t$ is in 3rd quadrant, so value of

$\bold{cot(t) =\dfrac{12}{5}}$

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Answer

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Step-by-step explanation:

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Lyrx [107]

Answer:

hey there long time!(〃ﾟ3ﾟ〃)

Step-by-step explanation:

your answer is B-34

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3 years ago