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Natalka [10]
3 years ago
10

You’re working at a concrete company that specializes in commercial-grade columns. A cylindrical column with a diameter of 3 fee

t and height of 10 feet is to be made of concrete. How many cubic yards of concrete are needed to fabricate the column?
Mathematics
2 answers:
NikAS [45]3 years ago
8 0
The answer to this question requires a formula. This formula is pie x radius squared x the height of the cylinder. The diameter is 3 feet, so it's radius is 1.5 feet. Square that and you get 2.25 feet. Take this and multiply it by pie. Most teachers simplify it to 3.14, to make it easier. So the value we have right now is 7.065 feet. Finally, we multiply this value by the height of the cylinder. We take 7.065 and multiply it by 10. The answer is 70.65 ft cubed. We are not done yet, because the question wants yards, not feet. So, the answer is 23.55 cubic yards. All I had to do was divide the value by 3 to get yards. I hope this answers your question as it should. Sorry for over explaining.
antiseptic1488 [7]3 years ago
4 0

Answer:

A. 2.62 cubic yards

Step-by-step explanation:Find the volume of the cylinder. Remember that 1 cubic yard = 27 cubic feet. See the Geometric Formulas table to find the volume of a cylinder.

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\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})

We have been given two vectors $\vec{a}$ and $\vec{b}$, we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

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The scalar projection of$\vec{b}$onto $\vec{a}$means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

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$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

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