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2 years ago

The chief advantage of the metric system over other system of measurement is that it

Chemistry

1 answer:

kolbaska11 [484]2 years ago

6 0

Answer:

The metric system goes by powers of ten, so it's very easy to measure. That would be the main advantage, measurements of ten. We can also say it's the most used measurement around the world, so all scientists have little to no conversion, but the main answer is probably the first one :)

You might be interested in

What is true if a liquid and a gas are in equilibrium?

MAXImum [283]

Answer:

A - Liquid molecules forming a gas and gas molecules forming a

liquid are equal in number.

Explanation:

A P E X

6 0

3 years ago

How many Liters of space will a 70.0g sample of CO2 occupy?

Tanzania [10]

Answer:

35.6 liters at STP

Explanation:

The molar mass of carbon dioxide is about 44.01 g/mol. The volume of a mole of ideal gas at STP is 22.4 L, so the volume of 70.0 g will be ...

(70.0g)/(44.01 g/mol)·(22.4 L/mol) ≈ 35.6 L

5 0

3 years ago

A student has a 2.19 L bottle that contains a mixture of O 2 , N 2 , and CO 2 with a total pressure of 5.57 bar at 298 K . She k

Sergeeva-Olga [200]

Answer: The partial pressure of oxygen gas is 2.76 bar

Explanation:

To calculate the number of moles, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 5.57 bar

V = Volume of the gas = 2.19 L

T = Temperature of the gas = 298 K

R = Gas constant = $0.0831\text{ L bar }mol^{-1}K^{-1}$

n = Total number of moles = ?

Putting values in above equation, we get:

$5.57bar\times 2.19L=n\times 0.0831\text{ L. bar }mol^{-1}K^{-1}\times 298K\\\\n=\frac{5.57\times 2.19}{0.0831\times 298}=0.493mol$

To calculate the mole fraction of carbon dioxide, we use the equation given by Raoult's law, which is:

$p_{A}=p_T\times \chi_{A}$ ........(1)

where,

$p_A$ = partial pressure of carbon dioxide = 0.318 bar

$p_T$ = total pressure = 5.57 bar

$\chi_A$ = mole fraction of carbon dioxide = ?

Putting values in above equation, we get:

$0.318bar=5.57bar\times \chi_{CO_2}\\\\\chi_{CO_2}=\frac{0.381}{5.57}=0.0571$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

We are given:

Moles of nitrogen gas = 0.221 moles

Mole fraction of nitrogen gas, $\chi_{N_2}=\frac{0.221}{0.493}=0.448$

Calculating the partial pressure of oxygen gas by using equation 1, we get:

Mole fraction of oxygen gas = (1 - 0.0571 - 0.448) = 0.4949

Total pressure of the system = 5.57 bar

Putting values in equation 1, we get:

$p_{O_2}=5.57bar\times 0.4949\\\\p_{O_2}=2.76bar$

Hence, the partial pressure of oxygen gas is 2.76 bar

6 0

3 years ago

The coordination sphere of a complex consists of ________. The coordination sphere of a complex consists of ________. the ligand

sammy [17]

Answer:

The coordination sphere of a complex consists of the central metal ion and the ligands bonded to it.

Explanation:

The Coordination Compounds are sets of a central metal ion attached to a group of molecules or ions that surround it. They are also called metal complexes or simply complexes. Then they are compounds that have a central atom surrounded by a group of molecules or ions, the latter called ligands.

The central atom must have empty orbitals capable of accepting pairs of electrons, with the transition metals being the ones with the greatest tendency. Because of this, they can act as Lewis acids (electron pair acceptors). The ligands have unshared electron pairs, then acting as Lewis bases (electron pair donors).

When forming a complex, it is said that the ligands coordinate to the metal and the central metal and the ligands attached to it constitute the coordination sphere of the complex.

Finally, the coordination sphere of a complex consists of the central metal ion and the ligands bonded to it.

5 0

3 years ago

What is the specific heat of a substance if 25 grams rises in temperature from 10 degrees Celsius to 25 degrees with the additio

Marina86 [1]

Answer:

0.75 cal/g°c

Explanation:

for specific heat we have formula:

Amount of heat absorbed or released = mass x specific heat of a substance x change in temperature.

ΔQ=m x c x ΔT

where c= specific heat

m= mass of a substance

ΔT = total temperature

ΔQ = Amount of heat

so for specific heat,

c= ΔQ/mxΔT

c= 280/25x (25-10)

c= 280/375

c= 0.75 cal/g°c

4 0

3 years ago