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Doss [256]
3 years ago
7

Two seventh grade math classes are competing in an academic challenge. Each class will randomly select one class member to compe

te each week. Each class has 26 students, and half of the students in each class are boys.
The classes want to design a simulation that will give the probability of both class members participating in the academic challenge being girls. Two possible simulations are given below.

Simulation 1: Flip a coin 26 times. If it lands on heads, count the flip as a girl. If it lands on tails, count the flip as a boy. Count how many times the coin lands on heads.

Simulation 2: Use two standard decks of cards. Randomly draw one card from each deck. Each diamond or heart drawn will represent a girl. Each spade or club drawn will represent a boy. After the two cards are drawn, they are replaced and the decks are shuffled. Count how many times a heart or diamond is drawn from both decks for 100 trials.
(Simuation 1 or Simulation 2) would be best to use to simulate a girl being randomly selected from each class to participate in the academic challenge. Based on this simulation, the probability that two girls will be selected is about (15%, 50%, 25%, or 75%).
Mathematics
1 answer:
erastovalidia [21]3 years ago
7 0
Probability of a coin flip would be 50%
probability f a red card = 50%

50% x 50% = 25%
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3 years ago
On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)
xz_007 [3.2K]

Answer:

P = 10 + 2\sqrt{53} units

Step-by-step explanation:

Given

Shape: Kite WXYZ

W (-3, 3),  X (2, 3),

Y (4, -4),  Z (-3, -2)

Required

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d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

For WX:

(x_1, y_1)\ (x_2,y_2) = (-3, 3),\ (2, 3)

WX = \sqrt{(-3 - 2)^2 + (3 - 3)^2}

WX = \sqrt{(-5)^2 + (0)^2}

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For XY:

(x_1, y_1)\ (x_2,y_2) = (2, 3)\ (4,-4)

XY = \sqrt{(2 - 4)^2 + (3 - (-4))^2}

XY = \sqrt{-2^2 + (3 +4)^2}

XY = \sqrt{-2^2 + 7^2}

XY = \sqrt{4 + 49}

XY = \sqrt{53}

For YZ:

(x_1, y_1)\ (x_2,y_2) = (4,-4)\ (-3, -2)

YZ = \sqrt{(4 - (-3))^2 + (-4 - (-2))^2}

YZ = \sqrt{(4 +3)^2 + (-4 +2)^2}

YZ = \sqrt{7^2 + (-2)^2}

YZ = \sqrt{49 + 4}

YZ = \sqrt{53}

For ZW:

(x_1, y_1)\ (x_2,y_2) = (-3, -2)\ (-3, 3)

ZW = \sqrt{(-3 - (-3))^2 + (-2 - 3)^2}

ZW = \sqrt{(-3 +3)^2 + (-2 - 3)^2}

ZW = \sqrt{0^2 + (-5)^2}

ZW = \sqrt{0 + 25}

ZW = \sqrt{25}

ZW = 5

The Perimeter (P) is as follows:

P = WX + XY + YZ + ZW

P = 5 + \sqrt{53} + \sqrt{53} + 5

P = 5 + 5 + \sqrt{53} + \sqrt{53}

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6 0
4 years ago
Which expression can be simplified to find the slope of the trend line in the scatterplot?
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Answer:  \frac{35-21}{8-4}

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3 0
3 years ago
Read 2 more answers
Which one is correct for this question need help please
emmainna [20.7K]

Answer:

A is correct, 7 units. Hope this helps! :)

5 0
3 years ago
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Inga [223]

answer:

9/4

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good luck :)

hopefully, this helps

have a good day !!

7 0
3 years ago
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