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Juliette [100K]
3 years ago
5

How does the volume of an oblique cone change if the height is reduced to 2/3 of its original size and the radius is doubled

Mathematics
1 answer:
spayn [35]3 years ago
3 0

The volume of oblique cone =\frac{1}{3} \pi r^{2} h

Now radius is doubled is now it is 2r

And height is reduced to 2/3 of its original size that is 2/3 h

So plugging the values we get volume

New Volume = \frac{1}{3} \pi (2r)^2 (\frac{2}{3} h)

= \frac{1}{3} \pi 4r^2 (\frac{2}{3} h) = \frac{8}{6} \pi r^{2} h =\frac{8}{2} (\frac{1}{3} \pi r^{2} h )=4*(\frac{1}{3} \pi r^{2} h )

It means the volume becomes 4 times

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