Answer:
Correct option is
C
36.25
Modal class =30−40
So we have, l=30,f0=12,f1=32,f2=20 and h=10
⇒ Mode=l+2f1−f0f2f1−f0×h
=30+2×32−12−2032−12×10
=30+6.25
=36.25
∴ Mode =36.25
Reflection, i am guessing
N = 1/3 -0
n = 1/3
answer
n = 1/3
For this case we have the following inequality:

The first thing we must do is to graph the linear function:

Then, we must evaluate ordered pairs in the following way:
(x, y)
The ordered pairs that meet the inequality, will be included as part of the graph.
Therefore, the shaded region contains all the ordered pairs that meet the inequality.
Answer: See attached image.