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Bogdan [553]
3 years ago
14

Please help show your work and 20 points.

Mathematics
2 answers:
Bezzdna [24]3 years ago
6 0

Answer:

B. 439.82

Step-by-step explanation:

A=2πrh+2πr2

A=2(pi)(5)(9)+2(pi)(5) squared

A=282.74+152.07

A=439.8

-have a nice day

Montano1993 [528]3 years ago
3 0

Answer:

B. 439.82cm^2

Step-by-step explanation:

A=2\pirh +2\pir^{2}

A= 2\pi \\5(9) + 2\pi5^{2}

A=439.82 cm^2

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3 years ago
Use stoke's theorem to evaluate∬m(∇×f)⋅ds where m is the hemisphere x^2+y^2+z^2=9, x≥0, with the normal in the direction of the
ludmilkaskok [199]
By Stokes' theorem,

\displaystyle\int_{\partial\mathcal M}\mathbf f\cdot\mathrm d\mathbf r=\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S

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\mathbf r(t)=\langle 0,3\cos t,3\sin t\rangle

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\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=2\pi}\mathbf f(x(t),y(t),z(t))\cdot\dfrac{\mathrm d}{\mathrm dt}\langle x(t),y(t),z(t)\rangle\,\mathrm dt
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We can check this result by evaluating the equivalent surface integral. We have

\nabla\times\mathbf f=\langle1,0,0\rangle

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\mathrm d\mathbf S=(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv=\langle9\cos v\sin v,9\cos u\sin^2v,9\sin u\sin^2v\rangle\,\mathrm du\,\mathrm dv

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\displaystyle\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S=\int_{v=0}^{v=\pi/2}\int_{u=0}^{u=2\pi}9\cos v\sin v\,\mathrm du\,\mathrm dv=9\pi

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7 0
3 years ago
4ac + 3 - 2b + 2ac - 5
muminat

Answer

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Step-by-step explanation:

Let's simplify step-by-step.

4ac+3−2b+2ac−5

=4ac+3+−2b+2ac+−5

Combine Like Terms:

=4ac+3+−2b+2ac+−5

=(4ac+2ac)+(−2b)+(3+−5)

=6ac+−2b+−2

4 0
3 years ago
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What is the volume of the storage chest? Round your answer to the nearest tenth.
Doss [256]

Answer:

<u>2047.5 cubic inches</u>

Step-by-step explanation:

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<u><em>Length × Width × Height</em></u>

<u><em /></u>

============================================================

Given :

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⇒ Width = 7.5 in.

⇒ Height = 10.5 in.

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frosja888 [35]

Answer:

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x = 6

4 0
2 years ago
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