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2 years ago

Please help show your work and 20 points.

Mathematics

2 answers:

Bezzdna [24]2 years ago

6 0

Answer:

B. 439.82

Step-by-step explanation:

A=2πrh+2πr2

A=2(pi)(5)(9)+2(pi)(5) squared

A=282.74+152.07

A=439.8

-have a nice day

Montano1993 [528]2 years ago

3 0

Answer:

B. 439.82cm^2

Step-by-step explanation:

A=2 $\pi$ rh +2 $\pi$ $r^{2}$

A= 2 $\pi \\$ 5(9) + 2 $\pi$ $5^{2}$

A=439.82 cm^2

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A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon

fiasKO [112]

Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that $n = 603, \pi = \frac{142}{603} = 0.2355$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694$

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

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2 years ago

Write 0.414141414141 as a fraction?

igor_vitrenko [27]

Answer:

The fraction is 41/99.

Step-by-step explanation:

The steps are :

$let \: x \: be \: fraction,$