Question

A 2-m^3 rigid tank contains nitrogen gas at 500kPa and 300K. Now the gas is compressed isothermally to a volume of 0.1 m. The work done on the gas during this compression process is: (a) 950 kJ (b) 0 kJ (c) 1610 kJ (d) 2996 kJ (e) 562 kJ

Answer 1

Answer:

(d) 2996 kJ

Explanation:

We have given initial volume $v_1=2m^3$

initial pressure $p_1=500\ kPa$

initial temperature $T_1=300\ K$

we know that during  isothermal process the work done is given by

$W=p_1v_1ln\frac{v_2}{v_1}$

where $v_2= final\ volume =0.1m^3\ given$

putting all these value in formula of work done

$W=500\times 2\times ln\frac{0.1}{2}$

=-2995.8 kJ here negative sign indicates that work is dine on the gas

so wok done =2995.8 kJ