Answer:
73.4846922835 = 73.5 and no it is not a perfect square 5400/100 = 54
 
        
             
        
        
        
To solve this we are going to use the future value of annuity due formula: 
![FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n})^{kt}-1 }{ \frac{r}{n} } ]](https://tex.z-dn.net/?f=FV%3D%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%20%29%2AP%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bkt%7D-1%20%7D%7B%20%5Cfrac%7Br%7D%7Bn%7D%20%7D%20%5D)
where

 is the future value

 is the periodic deposit 

 is the interest rate in decimal form 

 is the number of times the interest is compounded per year

 is the number of deposits per year
We know for our problem that 

 and 

. To convert the interest rate to decimal form, we are going to divide the rate by 100%: 

. Since Ruben makes the deposits every 6 months, 

. The interest is compounded semiannually, so 2 times per year; therefore, 

.
Lets replace the values in our formula:
![FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n})^{kt}-1 }{ \frac{r}{n} } ]](https://tex.z-dn.net/?f=FV%3D%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%20%29%2AP%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bkt%7D-1%20%7D%7B%20%5Cfrac%7Br%7D%7Bn%7D%20%7D%20%5D)
![FV=(1+ \frac{0.1}{2} )*420[ \frac{(1+ \frac{0.1}{2})^{(2)(15)}-1 }{ \frac{01}{2} } ]](https://tex.z-dn.net/?f=FV%3D%281%2B%20%5Cfrac%7B0.1%7D%7B2%7D%20%29%2A420%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7B0.1%7D%7B2%7D%29%5E%7B%282%29%2815%29%7D-1%20%7D%7B%20%5Cfrac%7B01%7D%7B2%7D%20%7D%20%5D)
 We can conclude that the correct answer is
We can conclude that the correct answer is <span>
$29,299.53</span>
 
        
        
        
Answer:
y= 3x+ 1
Step-by-step explanation:
-3x   +   2y =2
+3x            +3x
---------------------
2y = 3x +2
-----   --------
2           2
y = 3x + 1
 
        
             
        
        
        
Answer:
No! The answer is not zero. There can be infinite solutions for this equation.
Hope it helps!
 
        
                    
             
        
        
        
Answer:
In its simplest form the domain is all the values that go into a function, and the range is all the values that come out.
Step-by-step explanation: