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Ronch [10]
3 years ago
9

If f(x) = 2x^2 + 4, find f(3)

Mathematics
2 answers:
Trava [24]3 years ago
4 0

Answer:

f(3)=2(3)^2+4

f(3)=2(9)+4

f(3)=18+4

f(3)=22

Step-by-step explanation:

In this scenario, x=3 so you plug it into the other side of the equation.

Alexxx [7]3 years ago
4 0

<u>ANSWER</u>

f(3) = 22

<u>EXPLANATION</u>

The given given function is

f(x) = 2 {x}^{2}  + 4

To find f(3), we substitite x=3 into the function f(x).

This means that wherever we see x in

f(x) = 2 {x}^{2}  + 4

we replace it with 3 .

\implies \: f(3) = 2 ({3})^{2}  + 4

We evaluate the square to get:

\implies \: f(3) = 2 ({9})  + 4

Perform the multiplication

\implies \: f(3) = 18  + 4

Now add to get:

\implies \: f(3) = 2 2

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Sovle for x. 2x + 6 = - r - 15
Igoryamba

Answer:

x = \frac{-r - 21}{2}

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other.  Remember to do the opposite of PEMDAS.

PEMDAS =

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

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~

6 0
3 years ago
What is the perimeter of the figure in the diagram (round to three decimal places if necessary)?
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So any horizontal sides we can add based upon their length in x-values and any vertical sides we can add based upon their length in y-values. The diagonal sides we can find by the distance formula:
d =  \sqrt{( {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} }
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D) 28.472

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