1 answer:
Answer:
Area of the figure = 42 units²
Step-by-step explanation:
Area of the given figure = Area of rectangle JKIG - (Area of ΔEJD + Area of ΔCKD + Area of ΔCIH + Area of ΔEFG)
Area of rectangle JKIG = JK × JG
= 8 × 8
= 64 units²
Area of ΔEJD = 
= 
= 9 units²
Area of ΔCKD = 
= 
= 5 units²
Area of ΔCIH = 
= 
= 3 units²
Area of ΔEFG = 
= 
= 5 units²
Area of the given figure = 64 - (9 + 5 + 3 + 5)
= 64 - 22
= 42 units²
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<h3>
For example:</h3>
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Hope this helps...
Good luck on your assignment..