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Sphinxa [80]
3 years ago
13

WILL MARK BRAINLIEST

Mathematics
1 answer:
LuckyWell [14K]3 years ago
4 0

Answer:

Area of the figure = 42 units²

Step-by-step explanation:

Area of the given figure = Area of rectangle JKIG - (Area of ΔEJD + Area of ΔCKD + Area of ΔCIH + Area of ΔEFG)

Area of rectangle JKIG = JK × JG

                                      = 8 × 8

                                      = 64 units²

Area of ΔEJD = \frac{1}{2}(EJ)(JD)

                       = \frac{1}{2}(6)(3)

                       = 9 units²

Area of ΔCKD = \frac{1}{2}(CK)(KD)

                        = \frac{1}{2}(5)(2)

                        = 5 units²

Area of ΔCIH = \frac{1}{2}(CI)(IH)

                      = \frac{1}{2}(3)(2)

                      = 3 units²

Area of ΔEFG = \frac{1}{2}(FL)(EG)

                       = \frac{1}{2}(5)(2)

                       = 5 units²

Area of the given figure = 64 - (9 + 5 + 3 + 5)

                                         = 64 - 22

                                         = 42 units²

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