Answer:
The value of the test statistic is 
Step-by-step explanation:
The formula for the test statistic is:

In which X is the statistic,
is the mean,
is the standard deviation and n is the number of observations.
In this problem, we have that:

So



The value of the test statistic is 
Answer:

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795
Step-by-step explanation:
Given
See attachment for class
Solving (a): Fill the midpoint of each class.
Midpoint (M) is calculated as:

Where
Lower class interval
Upper class interval
So, we have:
Class 63-65:

Class 66 - 68:

When the computation is completed, the frequency distribution will be:

Solving (b): Mean and standard deviation using 1-VarStats
Using 1-VarStats, the solution is:


<em>See attachment for result of 1-VarStats</em>
Answer:
35
Step-by-step explanation:
We have to solve the problems in the parenthesis first.
(16-2÷2)= (16-1)=(15)
20÷2-15÷3
(20÷2)-(15÷3)
10-5=5
50-5= 45
80-45= 35
Hope this helps!
Answer:I don't know this one.
Step-by-step explanation:
Answer:
A. `1/2` foot
Step-by-step explanation:
The computation of the width of the box is shown below:
15 ÷ 28 = (5 ÷ 7)(1 1 ÷ 2)(width)
15 ÷ 28 = (5 ÷ 7)(3 ÷ 2)width
15 ÷ 28 = (15 ÷ 14)width
(15 ÷ 28) ÷ (15 ÷ 14) = width
(15 ÷ 28) × (14 ÷ 15) = width
w = 14 ÷ 28
= 1 ÷ 2 ft