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3 years ago

Solve x^2-8x-9=0 using completing the square (show the work)

Mathematics

1 answer:

Elden [556K]3 years ago

3 0

Answer: x=9,-1

Step-by-step explanation:

First, we are gonna start out with finding two numbers that multiply to equal -9 and add up to equal -8

Those numbers would be -9 & 1

-9+1=-8

-9x1=-9

Now we have

(x-9)(x+1)

x-9=0 x+1=0

+9 +9 -1 -1

x=9 x=-1

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Dimas [21]

Answer:

The simplest radical form is $9\sqrt{5}$ ⇒ (c)

Step-by-step explanation:

To simplify any square root;

Factorize the number under the root using prime numbers

Take out the root any number repeated twice as one number

Examples:

1. Simplify $\sqrt{8}$

factorize 8 using prime numbers

8 = 2 × 2 × 2, then $\sqrt{8}=\sqrt{(2)(2)(2)}$

Take two of 2 out the root, then $\sqrt{8}=2\sqrt{2}$

2. Simplify $\sqrt{18}$

factorize 18 using prime numbers

18 = 2 × 3 × 3, then $\sqrt{18}=\sqrt{(2)(3)(3)}$

Take the two 3 out the root, then $\sqrt{18}=3\sqrt{2}$

Let us simplify $3\sqrt{45}$

∵ 45 = 3 × 3 × 5

∴ $3\sqrt{45}=3\sqrt{(3)(3)(5)}$

→ Take the two 3 out by one 3

∴ $3\sqrt{45}=3(3)\sqrt{5}$

→ Multiply the numbers out the root

∴ $3\sqrt{45}=9\sqrt{5}$

∴ The simplest radical form is $9\sqrt{5}$

8 0

3 years ago

Please help will give 30 points

swat32

2.) 8/12 + 8/4= 2 2/3

3.) 2/8 + 6/10= 17/20

4.) 1/6 + 6/18 = 1/2

Hoped this helped!

5 0

3 years ago