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Oksi-84 [34.3K]
3 years ago
10

If p is a given sample proposition n is the sample size, and a is the number of standard deviations at a confidence level, what

is the standard error of the proportion?
Mathematics
1 answer:
Bas_tet [7]3 years ago
5 0

Answer:

The standard error of a proportion p in a sample of size n is given by: s = \sqrt{\frac{p(1-p)}{n}}

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question:

The standard error of a proportion p in a sample of size n is given by: s = \sqrt{\frac{p(1-p)}{n}}

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✿————✦————✿

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7 0
2 years ago
Complete the blank with either ∈ or ∉ so that the resulting statement is true. −2​__{−6,−3,−5,−1}
Misha Larkins [42]

Answer:

−2​ ∉ {−6,−3,−5,−1}

Step-by-step explanation:

Given

Set = {−6,−3,−5,−1}

Element = -2

Required

The interpretation of the question is to state if -2 is an element of the given set or not

The first thing to do is to check through the set to count the number of occurrence of -2

Looking through Set = {−6,−3,−5,−1}, we have that the occurrence of -2 is 0

This implies that -2 is not an element of the given set and this is represented by the symbol ∉

Hence:

−2​ ∉ {−6,−3,−5,−1}

7 0
3 years ago
What is the area of a rectangular stage that is 48 feet long and 30 feet wide?
zhannawk [14.2K]

The area of the rectangle is 1,440 cm2.

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3 years ago
For waht values of x do the vectors -1,0,-1), (2,1,2), (1,1, x) form a basis for R3?
DaniilM [7]
<h2>Answer:</h2>

The values of x for which the given vectors are basis for R³ is:

                        x\neq 1

<h2>Step-by-step explanation:</h2>

We know that for a set of vectors are linearly independent if the matrix formed by these set of vectors is non-singular i.e. the determinant of the matrix formed by these vectors is non-zero.

We are given three vectors as:

(-1,0,-1), (2,1,2), (1,1, x)

The matrix formed by these vectors is:

\left[\begin{array}{ccc}-1&2&1\\0&1&1\\-1&2&x\end{array}\right]

Now, the determinant of this matrix is:

\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-1(x-2)-2(1)+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+2-2+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+1

Hence,

-x+1\neq 0\\\\\\i.e.\\\\\\x\neq 1

4 0
3 years ago
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