Answer:
a) 580 - 16n
b) 9850 - 271.72n
Step-by-step explanation:
a) starting number of bales = 580
each day, the farmer feeds out 2 bales of hay to each yard. he has 8 yards, so he feeds out 2 bales 8 times for a total of 2 * 8 = 16 bales. Therefore, he loses 16 bales each day
After the first day, he has 580-16 = 564 bales. After the second, he has 564-16 = 548 bales, and so on. He loses 16 bales n times for n days, and as a result, his final amount of bales is
original amount - amount lost = 580 - 16n
b)
First, we can calculate how much a bale weighs.
average = sum/count = 9850 kg / 580 ≈ 17 kg
Therefore, as he loses 16 bales of hay, he loses 17 kg 16 times, or approximately 271.72 kg of hay every day. For n days, he loses 271.72n kg. This brings his final amount to be
starting - amount lost = 9850 - 271.72n
Answer:
- 90
Step-by-step explanation:
Answer:
1. A
2. B
Step-by-step explanation:
1. Only option A creates that graph, the other options are either backwards or are on top of each other.
2. Because the two lines are parallel, and do not intersect at all, there will be 0 solutions.
Answer:
((2 x^2 + 1)^2)/(x^2)
Step-by-step explanation:
Simplify the following:
(2 x + 1/x)^2
Hint: | Put the fractions in 2 x + 1/x over a common denominator.
Put each term in 2 x + 1/x over the common denominator x: 2 x + 1/x = (2 x^2)/x + 1/x:
((2 x^2)/x + 1/x)^2
Hint: | Combine (2 x^2)/x + 1/x into a single fraction.
(2 x^2)/x + 1/x = (2 x^2 + 1)/x:
((2 x^2 + 1)/x)^2
Hint: | Distribute exponents over quotients in ((2 x^2 + 1)/x)^2.
Multiply each exponent in (2 x^2 + 1)/x by 2:
Answer: ((2 x^2 + 1)^2)/(x^2)
Answer:
B
Step-by-step explanation:
Using the law of sines, we can make a proportion.
But first, we'll need to solve for the unknown angle.
We add up the two known angles and subtract that by 180.
90 + 41 = 131
180 - 131 = 49
So the unknown angles is 49.
Then, we can use the law of sines.
Make the equation.
sin(90)/55 = sin(49)/x
Simplify this using a calculator and you get around 41.51 or option B.
