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NikAS [45]
3 years ago
14

Can You Help Me!!!!!!!

Mathematics
1 answer:
Orlov [11]3 years ago
8 0
Y = -4/3x + 1 or can be 3y = -4x + 3
they are both the same
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An object is launched from a launching pad 208 ft. above the ground at a velocity of 192ft/sec. what is the maximum height reach
loris [4]

Answer:

The maximum height is 784 feet

Step-by-step explanation:

In this problem we use the kinematic equation of the height h of an object as a function of time

h(t) = -16t ^ 2 + v_0t + h_0

Where v_0 is the initial velocity and h_0 is the initial height.

We know that

v_0 = 192\ \frac{ft}{sec}

h_0 = 208\ ft.

Then the equation of the height is:

h(t) = -16t ^ 2 + 192t +208

For a quadratic function of the form ax ^ 2 + bx + c

where a

the maximum height of the function is at its vertex.

The vertice is

x = -\frac{b}{2a}\\\\y = f(\frac{-b}{2a})

In this case

a = -16\\b = 192\\c = 208

Then the vertice is:

t = -\frac{192}{2(-16)}\\\\t = 6\ sec

Now we calculate h (6)

h(6) = -16(6) ^ 2 +192(6) +208\\\\h(6) = 784\ feet

The maximum height is 784 feet

8 0
3 years ago
Make m the subject in a(c+m)=2(c+3m)
Murrr4er [49]

Answer:

m = \frac{2c-ac}{a-6}

Step-by-step explanation:

distribute parenthesis on both sides

ac + am = 2c + 6m ( collect terms in m on left side )

subtract 6m from both sides

ac + am - 6m = 2c ( subtract ac from both sides )

am - 6m = 2c - ac ( factor left side )

m(a - 6) = 2c - ac ( divide both sides by (a - 6))

m = \frac{2c-ac}{a-6}


3 0
3 years ago
Karabo is training by running for the Comrades Marathon ; he starts his training by running 40km per week . Each week he increas
sweet-ann [11.9K]

Answer:

hi

Step-by-step explanation:

hi

3 0
2 years ago
Please help don’t know answer
Aloiza [94]

Answer:

Step-by-step explanation: I think is a

? sorry if I'm incorrect :)

4 0
3 years ago
A number plus 18 is less than 28
andrezito [222]
Written as an inequality- x+18<28
8 0
2 years ago
Read 2 more answers
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