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Luda [366]
2 years ago
8

Solve with all work −4(2 + 9) + 3 = 6 − 4( − 3)

Mathematics
1 answer:
ra1l [238]2 years ago
3 0

Answer:

They do not equal eachother

Step-by-step explanation:

-4(2+9) + 3 = 6 - 4(-3)

-12 - 36 + 3 = 6 + 12

-45 = 18

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I need to find the X and Y values please help thanks
Anna35 [415]

Answer:

the 5y-23 equals 4  2x+13 equals 6.500

Step-by-step explanation:

thats what i worked out  and got

7 0
2 years ago
How much do I need to subtract from 67/10 to make 6
Harrizon [31]

Answer:

0.7

Step-by-step explanation:

67/10 is the same as 6.7 when you subtract the 0.7 you will remain with 6

4 0
2 years ago
Nya wants to buy a sweater that had an original price of $50. The sweater is now discounted 15% and the sales tax rate is 6%. Ho
Xelga [282]

Answer:

$45.05

Step-by-step explanation:

Sale price of sweater is (1.00 - 0.15)($50), or 0.85($50) = $42.50.  Nya has to pay 6% sales tax on this $42.50.  Thus, the final amount due is

(1.00 + 0.06)($2.50) = $45.05

6 0
2 years ago
Read 2 more answers
Which is a simplified form of the expression 6(2t – 3) + 3(t + 5)?
faust18 [17]

Answer:

it's option D.

Step-by-step explanation:

see attachment in case u need steps

8 0
3 years ago
Read 2 more answers
A certain city's population is 120,000 and decreases 1.4% per year for 15 years.
mart [117]

Answer:

  • Decay Problem.
  • Decay rate,  r = 0.014
  • Initial Amount =120,000
  • P(t)=120000(0.986)^t
  • P(10)=104,220

Step-by-step explanation:

The exponential function for growth/decay is given as:

P(t)=P_0(1 \pm r)^t, where:\\P_0$ is the Initial Population\\r is the growth/decay rate\\t is time

In this problem:

The city's initial population is 120,000 and it decreases by 1.4% per year.

  • Since the population decreases, it is a Decay Problem.
  • Decay rate, r=1.4% =0.014
  • Initial Amount =120,000

Therefore, the function is:

P(t)=120000(1 - 0.014)^t\\P(t)=120000(0.986)^t

When t=10 years

P(10)=120000(0.986)^10\\=104219.8\\\approx 104220 $ (to the nearest whole number)

8 0
3 years ago
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