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3 years ago

Solve with all work −4(2 + 9) + 3 = 6 − 4( − 3)

Mathematics

1 answer:

ra1l [238]3 years ago

3 0

Answer:

They do not equal eachother

Step-by-step explanation:

-4(2+9) + 3 = 6 - 4(-3)

-12 - 36 + 3 = 6 + 12

-45 = 18

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write an equation for the line that passes through the given point and has the given slope m (4,-5);m= -1/4

EastWind [94]

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Answer: $\textsf{y = -1/4x - 4}$

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Given: $\textsf{Slope = -1/4, Point through = (4, -5)}$

Find: $\textsf{Equation for the line that passes through the given point}$

Solution: In order to get the equation, we need to first use the point-slope form to help us sort out our information and then we solve for y.

Plug in the values

$\textsf{y - y}_1\textsf{ = m(x - x}_1\textsf{)}$

$\textsf{y - (-5) = -1/4(x - 4)}$

Simplify and solve for y

$\textsf{y + 5 = -1/4(x - 4)}$

$\textsf{y + 5 = -1/4x + 1}$

$\textsf{y + 5 - 5 = -1/4x + 1 - 5}$

$\textsf{y = -1/4x - 4}$

Therefore, the final answer would be that the equation that has a slope of -1/4 and passes through (4, -5) is y = -1/4x - 4.

5 0

2 years ago

Line CD passes through points C(3, -5) and D(6, 0). What is the equation off three line CD in standard form?

Alina [70]

Standard form: Ax+By=C
first put in slope-intercept form:
slope = (0+5)/(6-3) = 5/3
pick point D: 0 = 5/3(6)+b -> b= -10
slope-intercept form: y=(5/3)x-10
multiply both sides by 3:
3y=5x-30
put in standard form:
5x-3y=30

8 0

3 years ago

Read 2 more answers

What is the interquartile range (IQR) of the following data set 17 16 21 15 25 22 18 23 17

Pepsi [2]

IQR = 6

First locate the median $Q_{2}$ at the centre of the data arranged in ascending order. Then locate the lower and upper quartiles $Q_{1}$ and $Q_{3}$ located at the centre of the data to the left and right of the median.

Note that if any of the above are not whole values then they are the average of the values either side of the centre.

rearrange data in ascending order

15 16 ↓17 17 18 21 22 ↓23 25

↑

$Q_{2}$ = 18

$Q_{1}$ = $\frac{16+17}{2}$ = 16.5

$Q_{3}$ = $\frac{22+23}{2}$ = 22.5

IQR = $Q_{3}$ - $Q_{1}$ = 22.5 - 16.5 = 6

4 0

3 years ago

The equations -6x + 3y = 6 and x² + y = 10 intersect at the

eimsori [14]

The values of the letters in coordinates (a, b) and (c,d) are;

a = -4

b = -6

c = 2

d = 6

We are given two equations;

-6x + 3y = 6 ---(eq 1)

x² + y = 10 ---(eq 2)

We are told that they intersect at coordinates; (a, b) and (c, d).

Let us make y the subject in eq 2 to get;

y = 10 - x² --(eq 3)

Let us put 10 - x² into eq 1 to get;

-6x + 3(10 - x²) = 6

expanding further gives;

-6x + 30 - 3x² = 6

rearranging gives;

3x² + 6x - 24 = 0

Using online quadratic equation solver, we have;

x = -4 and x = 2

Putting x = -4 into eq 3 gives;

y = 10 - (-4)²

y = 10 - 16

y = -6

Putting x = 2 into eq 3 gives;

y = 10 - (2)²

y = 10 - 4

y = 6

Thus, the coordinates are; (-4, -6) and (2, 6)

Comparing with (a, b) and (c,d), we have;

a = -4

b = -6

c = 2

d = 6

Read more at; brainly.com/question/15165519

5 0

2 years ago

A gambling casino is designed in the shape of a square pyramid with a side length of 75 ft. The height of the building is 28 ft.

irakobra [83]

Answer:

Step-by-step explanation:

Given the dimension of a square pyramid

Length of pyramid

L = 75 ft

Height of pyramid

H = 28ft

The pyramid is a square base

Then,

Volume of a pyramid is calculated using

Volume = base area × height

Since base is a square, then the area of a square is

Area = L² = 75² = 5625 ft²

Then,

Volume = base Area × height

Volume = 5625 × 28

Volume = 157,500 ft³

Then, given the rate of volume to be

dV / dt = 26,250 ft³ / hr

So, we want to find the time the system will filled the air

dV / dt = 26,250

dV = 26,250 dt

Integrate both sides

∫ dV = ∫ 26,250 dt

V = 26,250t + C

When t = 0, V = 0, initially, there is not volume of system air.

Therefore C = 0

V = 26,250t

When V = 157,500 ft³

Then,

t = V / 26,250

t = 157,500 / 26,250

t = 6 hours

So, it will take 6 hours for the system to circulate the room

5 0

3 years ago