What's 235 divided by 40 but can you please show work

A square is cut in half on the diagonal creating two equal triangles each triangle has an area of 0.72 square units what is the

Katyanochek1 [597]

In a square all 4 sides are equal, so when you cut it along the diagonal to make a triangle, both the base and the height of the triangle would be the same.

The area of a triangle is found by the formula 1/2 x base x height

Since the base and height are the same the formula becomes Area = 1/2 x S^2 ( where S is the length of a side).

The area is given as 0.72 square units.

Now you have 0.72 = 1/2 x S^2

First multiply both sides by 2:

1.44 = S^2

To find S, take the square root of both sides:

S = √1.44

S = 1.2

The side length is 1.2 units.

7 0

3 years ago

3rd time asking for helpppp plz answer number 3

finlep [7]

Answer:

B

Step-by-step explanation:

4 0

2 years ago

Heeelppp with this pleasee 30 points

Naddika [18.5K]

Look kid, this question has been up for 16 hours think its time to let it go......... hoped i helped. ✔verified✔

7 0

3 years ago

Read 2 more answers

Which of the following names the value of the 5s in the number 1,5547

vovikov84 [41]

Can u explain it little clearer, do u mean all the fives?

8 0

2 years ago

In a widget factory, machines A, B, and C manufacture, respectively, 20, 30, and 50 percent of the total. Of their output 6, 3,

steposvetlana [31]

Answer:

38.71% probability it was manufactured by machine A.

29.03% probability it was manufactured by machine B.

32.26% probability it was manufactured by machine C.

Step-by-step explanation:

We have these following probabilities:

A 20% probability that the chip was fabricated by machine A.

A 30% probability that the chip was fabricated by machine B.

A 50% probability that the chip was fabricated by machine C.

A 6% probability that a chip fabricated by machine A was defective.

A 3% probability that a chip fabricated by machine B was defective.

A 2% probability that a chip fabricated by machine C was defective.

The question can be formulated as:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

What are the probabilities that it was manufactured by machines A, B, and C?

Machine A

What is the probability that the widget was manufactures by machine A, given that it is defective?

P(B) is the probability that it was manufactures by machine A. So $P(B) = 0.20$

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine A. So $P(A/B) = 0.06$

P(A) is the probability that a widget is defective. This is the sum of 6% of 20%, 3% of 30% and 2% of 50%. So

$P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031$

So

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.2*0.06}{0.031} = 0.3871$

38.71% probability it was manufactured by machine A.

Machine B

What is the probability that the widget was manufactures by machine B, given that it is defective?

P(B) is the probability that it was manufactures by machine B. So $P(B) = 0.30$

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine B. So $P(A/B) = 0.03$

$P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031$

So

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.3*0.03}{0.031} = 0.2903$

29.03% probability it was manufactured by machine B.

Machine C

What is the probability that the widget was manufactures by machine C, given that it is defective?

P(B) is the probability that it was manufactures by machine C. So $P(B) = 0.50$

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine C. So $P(A/B) = 0.02$

$P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031$

So

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.5*0.02}{0.031} = 0.3226$

32.26% probability it was manufactured by machine C.

6 0

2 years ago