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4 years ago

15

What's 235 divided by 40 but can you please show work

1 answer:

mestny [16]4 years ago

5 0

Answer is 5.875. Hope you can read my work and this is helpful :)

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Which expression is equivalent to 18s+9t+36

tatuchka [14]

18(s+t/2+2)

18(s+t/2+2)

8 0

3 years ago

3x^2(x^3-1)+2x^3(2x^2+2) <br> Whats the simplified answer?

ahrayia [7]

Answer:

$\large\boxed{7x^5+4x^3-3x^2}$

Step-by-step explanation:

$3x^2(x^3-1)+2x^3(2x^2+2)\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\=(3x^2)(x^3)+(3x^2)(-1)+(2x^3)(2x^2)+(2x^3)(2)\qquad\text{use}\ a^na^m=a^{n+m}\\\\=3x^{2+3}-3x^2+4x^{3+2}+4x^3\\\\=3x^5-3x^2+4x^5+4x^3\qquad\text{combine like terms}\\\\=(3x^5+4x^5)-3x^2+4x^3\\\\=7x^5+4x^3-3x^2$

4 0

3 years ago

Which strategy did companies use to stop strikes from growing?

Nastasia [14]

Answer:

They hired workers to cross the picket line if a group of workers went on strike.

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers

Look at the system of equations below.

Paul [167]

Answer:

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=2,\:y=-1$

Step-by-step explanation:

Considering the system of the equation

$\begin{bmatrix}y=-2x+3\\ 4x-3y=11\end{bmatrix}$

$\mathrm{Subsititute\:}y=-2x+3$

$\begin{bmatrix}4x-3\left(-2x+3\right)=11\end{bmatrix}$

$\mathrm{Isolate}\:x\:\mathrm{for}\:4x-3\left(-2x+3\right)=11$

$4x-3\left(-2x+3\right)=11$

$4x+6x-9=11$

$10x-9=11$

$10x-9+9=11+9$

$10x=20$

$x=2$

$\mathrm{For\:}y=-2x+3$

$\mathrm{Subsititute\:}x=2$

$y=-2\cdot \:2+3$

$y=-1$

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=2,\:y=-1$

7 0

3 years ago

Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function.f(x) = 3x3 + 39x2 + 39x + 27

kramer

First, we can factor this to make it easier to solve:

3(x^3 + 13x^2 + 13x + 9)

Now, we can use the rational root theorem like so:

List factors of 9:

1, 3, 9.

List factors of 1:

1

Because of this, we know our possible rational roots are:

+/-1, +/-3, +/-9

If none of these zeros fit using the remainder theorem, then we know our roots will be irrational.

8 0

3 years ago