3 years ago

Please Help!!!

1 answer:

3 0

Answer:(1,-4)

Step-by-step explanation:

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Sonja [21]

Answer:

Second option: (-2,-3) and (1,0)

Step-by-step explanation:

Given the system of equations $\left \{ {{y = x^2 + 2x-3} \atop {y = x - 1}} \right.$ , you can rewrite them in this form:

$x^2 + 2x-3= x - 1$

Simplify:

$x^2 + 2x-3-x+1=0\\\\x^2+x-2=0$

Factor the quadratic equation. Choose two number whose sum be 1 and whose product be -2. These are: 2 and -1, then:

$(x+2)(x-1)=0\\\\x_1=-2\\\\x_2=1$

Substitute each value of "x" into any of the original equation to find the values of "y":

$y_1= (-2) - 1=-3\\\\y_2=(1)-1=0$

Then, the solutions are:

(-2,-3) and (1,0)

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