1) Move the non-x term to the right
x^2 +6x = -c
2) Divide the equation by the coefficient of x^2
(You don't have to because it is one).
3) Get the "x" coefficient, divide it by 2, square it then add it to both sides:
6 divided by 2 = 3
3^2 = 9
x^2 +6x +9 = -c +9
Take the square root of both sides
(x +3) = sq root (9 -c)
x = -3 + sq root (9 -c)
Y+y = 2y there is no other solution.
The domain of the equation are all the possible values of the independent variables that would make the equation reasonable, possible or true. In this item, the independent variable is r. This could take a value of 0 up to the point when m is equal to zero.
m = 30 - 3r = 0
r = 10
The domain is therefore [0, 10].
The range is the value of the dependent variable which would be from 0 to the point when no video game is played. This is, [0, 30].
The function is discrete because r and m cannot take every value in the number line.
The height of the rocket is modeled by the function:

If we observe this equation, we see that the function is quadratic. The shape of the quadratic function is parabolic and the maximum or minimum value of a parabola always lies at its vertex. In the given function, since the co-efficient of leading term (t²) is negative, so this parabola will have a maximum value at its vertex.
The vertex of parabola is given by:

b is the coefficient of t term. So b = 80
a is the coefficient of squared term. So a= - 16
So,

This means at 2.5 sec the height of rocket will be maximum. The maximum height will be:
Therefore, the maximum height of the rocket will be 100 feet.
If f varies jointly as q^2 and h, and f=96 when q=4 and h=3 then the value of q when f = 48 and h = 6 is 2
<u>Solution:</u>
Given that, f varies jointly as q^2 and h

And f=96 when q=4 and h=3
Now substitute f, q, h values in above formula


We have to find q when f=48 and h=6

Hence, the value of q is 2