Hi,
$f(1)=2*1^5-9*1^4+12*1^3-12*1^2+10*1-3\\
=2-9+12-12+10-3\\
=0\\

f(x)=(x-1)(2x^4-7x^3+5x^2-7x+3)\\


g(x)=2x^4-7x^3+5x^2-7x+3\\

g(3)=2*3^4-7*3^3+5*3^2-7*3+3\\
=162-189+45-21+3\\
=0\\

g(x)=(x-3)(2x^3-x^2+2x-1)\\

h(x)=2x^3-x^2+2x-1\\

h( \dfrac{1}{2} )=2* \dfrac{1}{8} - \dfrac{1} {4}+1-1\\
=0\\

h(x)=(2x-1)(x^2+1)\\


f(x)=(x-1)(x-3)(2x-1)(x+i)(x-i)\\


$
Roots are 1,3,0.5,i,-i.

8 0

3 years ago

Teresa is maintaining a camp fire. She has kept the fire steadily burning for 4 hours with 6 logs. She wants to know how many lo

elena-14-01-66 [18.8K]

Answer:

X/18=6/4

Step-by-step explanation:

4hrs=6 logs

18hrs=x

4x=18×6

Which can also be written as

$\frac{x}{18 } = \frac{6}{4}$

7 0

3 years ago

Please help me and I’ll give you brainiest!!!!!

algol [13]

Answer:

Step-by-step explanation:

8 0

3 years ago