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3 years ago

How much paint does Brielle need to finish her room

Mathematics

1 answer:

KATRIN_1 [288]3 years ago

4 0

Answer:

Paint Needed = 1.25 gallons = It means 1 gallon and 1 quart of paint is needed to paint the Briellie's room.

Step-by-step explanation:

As, this question is incomplete, so we will create similar question and complete it. '

Let's suppose Brielle's room has following dimensions:

Length of two walls = 10 ft

Length of other two walls = 12 ft

Height of the room from bottom to ceiling = 10 ft

In order to calculate the amount of paint needed, we need to calculate the surface area of the room to be painted.

So, for that, add all the lengths together and multiply it by height of the room.

SF = (L1 +L2 +L3+ L4) x H

SF = (10 + 10 + 12 + 12) x (10)

SF = 440 sq.ft = Actual footage of the room to be painted.

Now, we have convert this number in gallons to know the amount of paint required to paint Brielle's room. For this, we need to divide our SF to 350 sq.ft per gallon.

Paint Needed = 440 sq.ft / 350 sq.ft per gallon

Paint Needed = 1.25 gallons = It means 1 gallon and 1 quart of paint is needed to paint the Briellie's room.

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3 years ago

4. For graduation, Diamond was able to buy her first car for $24,000. Her parents gave her a present and made a

s344n2d4d5 [400]

Answer:

$403.15

Step-by-step explanation:

Principal loan amount is the total amount minus down-payment:

$Principal=24000-1000\\\\=23000$

Knowing that $n=12\times 6=72,P=23000, r=7.99\%/12=0.006658$ , the monthly payments can be calculated using the formula:

$M=P[\frac{r(1+r)^n}{(1+r)^n-1}]\\\\=23000\frac{(0.006658(1.006658)^{72}}{1.006658^{72}-1}\\\\=403.15$

Hence, the monthly payment is $403.15

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3 years ago

In a certain clinical study, 15% of participants were classified as heavy smokers, 25% as light-smokers, and the rest as non-smo

Natasha_Volkova [10]

Answer:

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

Step-by-step explanation:

We have the following probabilities:

A 15% probability that a participant is classified as a heavy smoker.

A 25% probability that a participant is classified as a light smoker.

A 100% - 25% - 15% = 60% probability that a participant is classified as a non smoker.

A x% probability that a non smoker dies.

A 3x% probability that a light smoker dies.

A 5x% probability that a heavy smoker dies.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

This problem is:

What is the probability of the participant being a non-smoker, given that he died?

P(B) is the probability that the participant is a non smoker. So

$P(B) = 0.6$

P(A/B) is the probability that the participant dies, given that he is a non smoker. So:

$P(A/B) = x$

P(A) is the probability that the participant dies:

$P(A) = P_{1} + P_{2} + P_{3}$

$P_{1}$ is the probability that a heavy smoker is selected and that he dies. So:

$P_{1} = 0.15*5x = 0.75x$

$P_{2}$ is the probability that a light smoker is selected and that he dies. So:

$P_{2} = 0.25*3x = 0.75x$

$P_{3}$ is the probability that a non-smoker is selected and that he dies. So:

$P_{3} = 0.60*x = 0.60x$

The probability that a participant dies is:

$P(A) = P_{1} + P_{2} + P_{3} = 0.75x + 0.75x + 0.60x = 2.10x$

The probability of the participant being a non-smoker, given that he died, is:

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.6x}{2.10x} = \frac{0.6}{2.10} = 0.2857$

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

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Answer:

Step-by-step explanation:

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