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Leto [7]
3 years ago
10

Suppose we have two binomial populations where the true proportion of success is .2 for the first population and .3 for the seco

nd population. We take an SRS of size 4 from the first population, and the number of successes is 3. We take an SRS of size 400 from the second population, and the number of successes is 200. What is a possible reason that is not close to .3
Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
7 0

Answer:

The value is not close to 0.3 because of sampling variability.

Step-by-step explanation:

The group of answer choices are not given which are as follows:  

  • All of the above
  • Because the sample size is too small  
  • Because of sampling variability  
  • Because of nonresponse bias

From this the correct option is option C which is Because of Sampling Variability.

This is true because the two populations are of different values and thus the sample is not dependent on any one of the two possibilities. When a sample of 4 is considered from first and 400 from the second the overall probability will be far from the value of 0.3. So the

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The mathematics department of a college has 10 male​ professors, 12 female​ professors, 12 male teaching​ assistants, and 15 fem
lana [24]

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Mkey [24]

Answer:

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Step-by-step explanation:

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2)  Collect like terms.

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3) Simplify.

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