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harkovskaia [24]
4 years ago
12

For supernova explosions caused by collasping cores, the core itself will either become a __________ or a ___________. (choose t

he two correct answers) black hole supernova remnant red dwarf neutron star white dwarf
Physics
2 answers:
Gnesinka [82]4 years ago
5 0

When supernova explodes because of the collapsing cores, the core itself will become a neutron star or a white dwarf without undergoing any kind of explosive transformation. The white dwarf stars can also become supernova if they orbit another star in a binary system and steal material from their companion. In addition, the end state of a star, whether it will explode as a supernova become a black hole.

 

Arturiano [62]4 years ago
5 0

Answer: For supernova explosions caused by collapsing cores, the core itself will either become a<u> </u><u>Black-hole </u>or a <u>Neutron Star</u>.

Explanation:

A massive star becomes a Red Super-giant towards the end of its journey. It goes supernova. The inner core becomes either a neutron star or a black-hole. The remnant becomes neutron star if the initial mass of the star is three to eight solar mass. Star having initial mass more than eight solar mass forms a black-hole after supernova.

Hence, the correct options are:

For supernova explosions caused by collapsing cores, the core itself will either become a<u> </u><u>Black-hole </u>or a <u>Neutron Star</u>.

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Which of the following is true concerning atoms?Atoms are made of even smaller substances called subatomic particles
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3 0
4 years ago
A block of mass m1 = 19.5 kg slides along a horizontal surface (with friction, μk = 0.35) a distance d = 2.6 m before striking a
worty [1.4K]

Answer:

19.5 m/s

87.8 m

Explanation:

The acceleration of block one is:

∑F = ma

-m₁gμ = m₁a

a = -gμ

a = -(9.8 m/s²) (0.22)

a = -2.16 m/s²

The velocity of block one just before the collision is:

v² = v₀² + 2aΔx

v² = (8.25 m/s)² + 2 (-2.16 m/s²) (2.3 m)

v = 7.63 m/s

Momentum is conserved, so the velocity of block two just after the collision is:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

m₁u₁ = m₂v₂

(18.5 kg) (7.63 m/s) = (7.25 kg) v

v = 19.5 m/s

The acceleration of block two is also -2.16 m/s², so the distance is:

v² = v₀² + 2aΔx

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7 0
3 years ago
What force is needed to give a 4800.0 kg truck an acceleration of 6.2 m/s2 over a level road? ​
tekilochka [14]

Answer:

the force needed to give the truck the acceleration is 29,760 N.

Explanation:

Given;

mass of truck, m = 4800 kg

acceleration of the truck, a = 6.2 m/s²

The force needed to give the truck the acceleration is calculated as;

F = ma

F = 4800 x 6.2

F = 29,760 N

Therefore, the force needed to give the truck the acceleration is 29,760 N.

6 0
3 years ago
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