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harkovskaia [24]
3 years ago
12

For supernova explosions caused by collasping cores, the core itself will either become a __________ or a ___________. (choose t

he two correct answers) black hole supernova remnant red dwarf neutron star white dwarf
Physics
2 answers:
Gnesinka [82]3 years ago
5 0

When supernova explodes because of the collapsing cores, the core itself will become a neutron star or a white dwarf without undergoing any kind of explosive transformation. The white dwarf stars can also become supernova if they orbit another star in a binary system and steal material from their companion. In addition, the end state of a star, whether it will explode as a supernova become a black hole.

 

Arturiano [62]3 years ago
5 0

Answer: For supernova explosions caused by collapsing cores, the core itself will either become a<u> </u><u>Black-hole </u>or a <u>Neutron Star</u>.

Explanation:

A massive star becomes a Red Super-giant towards the end of its journey. It goes supernova. The inner core becomes either a neutron star or a black-hole. The remnant becomes neutron star if the initial mass of the star is three to eight solar mass. Star having initial mass more than eight solar mass forms a black-hole after supernova.

Hence, the correct options are:

For supernova explosions caused by collapsing cores, the core itself will either become a<u> </u><u>Black-hole </u>or a <u>Neutron Star</u>.

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A tuba may be treated like a tube closed at one end. If a tuba has a fundamental frequency of 88.4 Hz, determine the first three
yulyashka [42]

Answer with Explanation:

We are given that

Fundamental frequency,f=88.4 Hz

Speed of sound,v=343 m/s

We have to find the first three overtones.

Tube is closed

The overtone of closed pipe  is equal to odd number of fundamental frequency.

Therefore, the overtone of tuba

f'=nf

Where n=3,5,7,..

Substitute n=3

f'=3\times 88.4=265.2Hz

For second overtone

f'=5\times 88.4=442Hz

For third overtone

f'=7\times 88.4=618.8Hz

4 0
3 years ago
An Earth satellite is orbiting at a distance from the Earth’s surface equal to one Earth radius (4 000 miles). At this location,
trasher [3.6K]

Answer:

The acceleration due to gravity is \dfrac{1}{4} times the value of g at the Earth’s surface.

(D) is correct option.

Explanation:

Given that,

Radius = 4000 miles

We need to calculate the gravitational force at surface

Gravitational force on the mass m on the surface of the earth

At r = R

F=mg

mg=\dfrac{GmM}{R^2}....(I)

We need to calculate the gravitational force at height

Gravitational force on a mass m from the center of the earth,

At r = R + R = 2 R

F'=mg'

mg'=\dfrac{GmM}{4R^2}....(II)

Dividing equation (II) by equation (I)

\dfrac{mg'}{mg}=\dfrac{\dfrac{GmM}{4R^2}}{\dfrac{GmM}{R^2}}

\dfrac{g'}{g}=\dfrac{1}{4}

Hence, The acceleration due to gravity is \dfrac{1}{4} times the value of g at the Earth’s surface.

4 0
3 years ago
The thermal energy of what system does change
Inessa05 [86]

Answer:

there is the increase the temperature of cold body and decrease the temperature of hot body

4 0
2 years ago
A stone dropped from the top of a 80m high building strikes the ground at 40 m/s after falling for 4 seconds. The stone's potent
Sergeu [11.5K]

Answer: c. 40m

Explanation:

See picture

3 0
3 years ago
Here on Earth you hang a mass from a vertical spring and start it oscillating with amplitude 1.9 cm. You observe that it takes 3
Vlada [557]

Answer:

T = 3.23 s

Explanation:

In the simple harmonic movement of a spring with a mass the angular velocity is given by

               w = √ K / m

With the initial data let's look for the ratio k / m

The angular velocity is related to the frequency and period

           w = 2π f = 2π / T

            2π / T = √ k / m

            k₀ / m₀ = (2π / T)²

            k₀ / m₀ = (2π / 3.0)²

            k₀ / m₀ = 4.3865

The period on the new planet is

          2π / T = √ k / m

           T = 2π √ m / k

In this case the amounts are

           m = 6 m₀

           k = 10 k₀

We replace

            T = 2π√6m₀ / 10k₀

            T = 2π √6/10 √m₀ / k₀

            T = 2π √ 0.6  √1 / 4.3865

            T = 3.23 s

5 0
3 years ago
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