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Lubov Fominskaja [6]

3 years ago

10

A 30%-efficient car engine accelerates the 1300 kg car from rest to 10 m/s . How much energy is transferred to the engine by bur

ning gasoline

1 answer:

WITCHER [35]3 years ago

3 0

Answer:

The Energy transferred to the engine by burning gasoline = <u>216.67 KJ</u>

Explanation:

The parameters given are:

The efficiency of the car engine, E = 30% = 0.3

Mass, m = 1300 kg

Initial velocity, u = 0, since the car is from rest

The final velocity, v = 10 m/s

Since the car was moving, we calculate its kinetic energy.

kinetic energy = ((1/2) (m) (v^2)

((1/2) (1300 kg) (10 m/s^2)

= 65,000 j

The Energy, Q transferred to the engine by burning gasoline in this case

= potential energy / The efficiency of the car engine, E

Q = 65,000 j / 0.3

= 216,666.66 J

Converting Joule to kilojoule

where 1KJ = 1000j

216,666.66 J = <u>216.67 KJ</u>

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<u>Electric Potential </u>

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Answer with Explanation:

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